Expresswala Academy Mathematics Tuition

Algebraic Expressions and Their Uses

MCQ test, Set 1

  • Set 1 of 10
  • 25 questions
  • 25 marks
  • 30 minutes

Download the PDF (with key sheet and solutions, 82.4 KB)

Choose one answer for each question, then check your score at the end. Each correct answer carries 1 mark; there is no negative marking.

  1. Which of the following is a constant?
    Answer and solution

    Answer: (D) −13-13

    A constant has a fixed value.

    −13-13 is a fixed number; the others contain the variable aa.

  2. "88 divided by mm" in symbolic form is
    Answer and solution

    Answer: (A) 8m\displaystyle \frac{8}{m}

    88 divided by mm is written 8m\displaystyle \frac{8}{m}.

    So it is 8m\displaystyle \frac{8}{m}.

  3. The number of terms in 6−3b34−5a3\displaystyle 6 - \frac{3b^3}{4} - 5a^3 is
    Answer and solution

    Answer: (B) 33

    Terms are separated by ++ and −- signs.

    The terms are 66, −3b34\displaystyle -\frac{3b^3}{4}, −5a3-5a^3.

    So there are 33 terms.

  4. 5mn25mn^2 written as a product of its factors is
    Answer and solution

    Answer: (C) 5×m×n×n5 \times m \times n \times n

    n2n^2 means nn multiplied 22 times.

    5mn2=5×m×n×n5mn^2 = 5 \times m \times n \times n

  5. The co-efficient of xz2xz^2 in 16xy2z2\displaystyle \frac{1}{6}xy^2z^2 is
    Answer and solution

    Answer: (A) 16y2\displaystyle \frac{1}{6}y^2

    16xy2z2=(16y2)×xz2\displaystyle \frac{1}{6}xy^2z^2 = \left(\frac{1}{6}y^2\right) \times xz^2

    So the co-efficient of xz2xz^2 is 16y2\displaystyle \frac{1}{6}y^2.

  6. Which of the following is a like term of −6a2b-6a^2b?
    Answer and solution

    Answer: (B) 9ba29ba^2

    Like terms have the same literal factors.

    9ba29ba^2 has the literal factors ba2=a2bba^2 = a^2b, the same as −6a2b-6a^2b.

  7. 9m+3+9m+7=9m + 3 + 9m + 7 =
    Answer and solution

    Answer: (C) 18m+1018m + 10

    9m+3+9m+79m + 3 + 9m + 7

    =(9+9)m+(3+7)= (9 + 9)m + (3 + 7)

    =18m+10= 18m + 10

  8. 2y−13y=2y - 13y =
    Answer and solution

    Answer: (A) −11y-11y

    2y−13y2y - 13y

    =(2−13)y= (2 - 13)y

    =−11y= -11y

  9. Which of the following is a trinomial?
    Answer and solution

    Answer: (C) −4c2+3b2−4b3-4c^2 + 3b^2 - 4b^3

    A trinomial has three monomials.

    −4c2+3b2−4b3-4c^2 + 3b^2 - 4b^3 has three terms.

  10. Which of the following is a multinomial but not a polynomial?
    Answer and solution

    Answer: (A) 3+4t\displaystyle 3 + \frac{4}{t}

    4t=4t−1\displaystyle \frac{4}{t} = 4t^{-1} has the power −1-1, so it is not a monomial.

    So 3+4t\displaystyle 3 + \frac{4}{t} is a multinomial but not a polynomial.

  11. The degree of −2p2q5t3-2p^2q^5t^3 is
    Answer and solution

    Answer: (D) 1010

    Add the powers of the variables:

    2+5+3=102 + 5 + 3 = 10

  12. The degree of 3m2+4m3n3−2m5n33m^2 + 4m^3n^3 - 2m^5n^3 is
    Answer and solution

    Answer: (B) 88

    Degrees of the terms are 2,6,82, 6, 8.

    The greatest is 88.

  13. The value of 4b−2c−54b - 2c - 5 when b=−5b = -5 and c=−2c = -2 is
    Answer and solution

    Answer: (D) −21-21

    Put b=−5b = -5 and c=−2c = -2:

    4(−5)−2(−2)−54(-5) - 2(-2) - 5

    =−20+4−5= -20 + 4 - 5

    =−21= -21

  14. The value of x2+3xz−2z2x^2 + 3xz - 2z^2 when x=2x = 2 and z=−1z = -1 is
    Answer and solution

    Answer: (D) −4-4

    Put x=2x = 2 and z=−1z = -1:

    (2)2+3(2)(−1)−2(−1)2(2)^2 + 3(2)(-1) - 2(-1)^2

    =4−6−2= 4 - 6 - 2

    =−4= -4

  15. The sum of 3n2−3t2+5nt3n^2 - 3t^2 + 5nt and 7n2+6t2+8nt7n^2 + 6t^2 + 8nt is
    Answer and solution

    Answer: (B) 10n2+3t2+13nt10n^2 + 3t^2 + 13nt

    3n2−3t2+5nt+7n2+6t2+8nt3n^2 - 3t^2 + 5nt + 7n^2 + 6t^2 + 8nt

    =(3+7)n2+(−3+6)t2+(5+8)nt= (3 + 7)n^2 + (-3 + 6)t^2 + (5 + 8)nt

    =10n2+3t2+13nt= 10n^2 + 3t^2 + 13nt

  16. The sum of 7a−5b7a - 5b, 3b−9m3b - 9m and 8a+5m8a + 5m is
    Answer and solution

    Answer: (D) 15a−2b−4m15a - 2b - 4m

    Add the like terms column by column:

    7a−5b3b−9m8a+5m15a−2b−4m\begin{array}{rrr} 7a & -5b & \\ & 3b & -9m \\ 8a & & +5m \\ \hline 15a & -2b & -4m \end{array}

  17. Subtract −9m-9m from 8m8m.
    Answer and solution

    Answer: (D) 17m17m

    (8m)−(−9m)(8m) - (-9m)

    =8m+9m= 8m + 9m

    =(8+9)m= (8 + 9)m

    =17m= 17m

  18. If A=6p2−4p+5A = 6p^2 - 4p + 5 and B=2p2+7p+9B = 2p^2 + 7p + 9, then A−2B=A - 2B =
    Answer and solution

    Answer: (B) 2p2−18p−132p^2 - 18p - 13

    (6p2−4p+5)−2(2p2+7p+9)(6p^2 - 4p + 5) - 2(2p^2 + 7p + 9)

    =6p2−4p+5−4p2−14p−18= 6p^2 - 4p + 5 - 4p^2 - 14p - 18

    =(6−4)p2+(−4−14)p+(5−18)= (6 - 4)p^2 + (-4 - 14)p + (5 - 18)

    =2p2−18p−13= 2p^2 - 18p - 13

  19. Subtract 5a2−2ac−75a^2 - 2ac - 7 from 6a2−16a^2 - 1.
    Answer and solution

    Answer: (C) a2+6+2aca^2 + 6 + 2ac

    Change the signs of 5a2−2ac−75a^2 - 2ac - 7 and add:

    6a2−15a2−7−2ac(−)(+)(+)a2+6+2ac\begin{array}{rrr} 6a^2 & -1 & \\ 5a^2 & -7 & -2ac \\ (-) & (+) & (+) \\ \hline a^2 & +6 & +2ac \end{array}

    =a2+6+2ac= a^2 + 6 + 2ac

  20. 5p3q×2p3q×3p2q=5p^3q \times 2p^3q \times 3p^2q =
    Answer and solution

    Answer: (B) 30p8q330p^8q^3

    Multiply the numbers and add the powers of the same letters:

    =(5×2×3)(p3×p3×p2)(q×q×q)= (5 \times 2 \times 3)(p^3 \times p^3 \times p^2)(q \times q \times q)

    =30p8q3= 30p^8q^3

  21. −4m2(7mp+3m2n−4m)=-4m^2(7mp + 3m^2n - 4m) =
    Answer and solution

    Answer: (D) −28m3p−12m4n+16m3-28m^3p - 12m^4n + 16m^3

    Multiply −4m2-4m^2 with every term inside the bracket:

    =(−4m2)(7mp)+(−4m2)(3m2n)+(−4m2)(−4m)= (-4m^2)(7mp) + (-4m^2)(3m^2n) + (-4m^2)(-4m)

    =−28m3p−12m4n+16m3= -28m^3p - 12m^4n + 16m^3

  22. (4q−8)(2q−6)=(4q - 8)(2q - 6) =
    Answer and solution

    Answer: (C) 8q2−40q+488q^2 - 40q + 48

    (a+b)(c+d)=ac+ad+bc+bd(a + b)(c + d) = ac + ad + bc + bd

    =8q2−24q−16q+48= 8q^2 - 24q - 16q + 48

    =8q2−40q+48= 8q^2 - 40q + 48

  23. (4y+z)(y−z)=(4y + z)(y - z) =
    Answer and solution

    Answer: (C) 4y2−3yz−z24y^2 - 3yz - z^2

    (a+b)(c+d)=ac+ad+bc+bd(a + b)(c + d) = ac + ad + bc + bd

    =4y2−4yz+yz−z2= 4y^2 - 4yz + yz - z^2

    =4y2−3yz−z2= 4y^2 - 3yz - z^2

  24. 6n(4n+t)−4t(3n+t)=6n(4n + t) - 4t(3n + t) =
    Answer and solution

    Answer: (A) 24n2−6nt−4t224n^2 - 6nt - 4t^2

    Multiply out each bracket and add like terms:

    =24n2+6nt−12nt−4t2= 24n^2 + 6nt - 12nt - 4t^2

    =24n2+(6−12)nt−4t2= 24n^2 + (6 - 12)nt - 4t^2

    =24n2−6nt−4t2= 24n^2 - 6nt - 4t^2

  25. y−{5y−(2z−7z)}=y - \{5y - (2z - 7z)\} =
    Answer and solution

    Answer: (A) −4y−5z-4y - 5z

    Remove the round brackets first, then the curly brackets:

    =y−{5y−2z+7z}= y - \{5y - 2z + 7z\}

    =y−{5y+5z}= y - \{5y + 5z\}

    =y−5y−5z= y - 5y - 5z

    =−4y−5z= -4y - 5z