How to use this set

Here are twelve ques­tions on the coor­di­nate plane. Please sketch every fig­ure, even a rough one. A quick sketch catches a sign error long before the arith­metic does. And when­ever you claim a shape, say which dis­tances you com­pared and why they set­tle the mat­ter.

Sec­tion A, Locat­ing points

  1. Write the quad­rant or axis of each point: (−3,7)(-3, 7), (0,−6)(0, -6), (8,−8)(8, -8), (−1,−1)(-1, -1), (5,0)(5, 0).
  2. A point KK has yy-coor­di­nate 44. Describe all the points like this. In which quad­rants can KK lie?
  3. The points A(−4,0)A(-4, 0), B(0,3)B(0, 3), C(4,0)C(4, 0) and D(0,−3)D(0, -3) are joined in order. With­out plot­ting, say which pairs of points are mir­ror images in an axis, and name the axis each time. Then say what shape ABCDABCD is, and give your rea­son.
  4. Plot (3,2)(3, 2), (−3,2)(-3, 2), (−3,−2)(-3, -2) and (3,−2)(3, -2). What shape do they form, and what are its side lengths?

Sec­tion B, Dis­tances

  1. Find the perime­ter of the tri­an­gle with ver­tices (0,0)(0, 0), (8,0)(8, 0) and (8,6)(8, 6).
  2. Show that (2,3)(2, 3), (8,3)(8, 3) and (5,3+33)(5, 3 + 3\sqrt{3}) are the ver­tices of an equi­lat­eral tri­an­gle.
  3. Are the points (−6,−2)(-6, -2), (0,2)(0, 2) and (9,8)(9, 8) on one straight line?
  4. A point PP is equidis­tant from A(2,0)A(2, 0) and B(0,6)B(0, 6) and lies on the xx-axis. Find PP.

Sec­tion C, Mid­points and cir­cles

  1. Find the mid­point of each side of the tri­an­gle (2,4)(2, 4), (8,4)(8, 4), (6,10)(6, 10).
  2. The mid­points of the sides of a tri­an­gle are D(4,2)D(4, 2), E(7,6)E(7, 6) and F(1,5)F(1, 5). Find the ver­tices. (Hint: the ver­tex oppo­site DD is found by using that EE and FF are mid­points of the two sides through it.)
  3. Check whether (6,8)(6, 8), (−10,0)(-10, 0) and (0,−10)(0, -10) lie on a cir­cle cen­tred at the ori­gin. If so, find its radius, and decide whether (7,7)(7, 7) is inside, on or out­side it.
  4. A screen is 640640 pix­els wide and 480480 high with the ori­gin at its bot­tom-left cor­ner. A cir­cu­lar icon of radius 6060 is cen­tred at (70,90)(70, 90); another of radius 9090 is cen­tred at (200,180)(200, 180). Does either icon run off the edge of the screen? And do the two icons over­lap?

Answers

Show answers
  1. II; yy-axis (below OO); IV; III; xx-axis (right of OO).
  2. All points on the hor­i­zon­tal line 44 units above the xx-axis. Quad­rant I when x>0x > 0, Quad­rant II when x<0x < 0; on the yy-axis when x=0x = 0.
  3. AA and CC are mir­ror images in the yy-axis; BB and DD in the xx-axis. All four sides are 16+9=5\sqrt{16 + 9} = 5, so ABCDABCD is a rhom­bus; its diag­o­nals AC=8AC = 8 and BD=6BD = 6 are unequal, so it is not a square.
  4. A rec­tan­gle: hor­i­zon­tal sides 66, ver­ti­cal sides 44.
  5. Sides 88, 66 and 64+36=10\sqrt{64 + 36} = 10. Perime­ter 2424.
  6. (2,3)(2, 3) to (8,3)(8, 3): 66. (2,3)(2, 3) to (5,3+33)(5, 3 + 3\sqrt{3}): 9+27=6\sqrt{9 + 27} = 6. (8,3)(8, 3) to (5,3+33)(5, 3 + 3\sqrt{3}): 9+27=6\sqrt{9 + 27} = 6. All equal.
  7. 36+16=52=213\sqrt{36 + 16} = \sqrt{52} = 2\sqrt{13}; 81+36=117=313\sqrt{81 + 36} = \sqrt{117} = 3\sqrt{13}; 225+100=325=513\sqrt{225 + 100} = \sqrt{325} = 5\sqrt{13}. Since 213+313=5132\sqrt{13} + 3\sqrt{13} = 5\sqrt{13}, yes.
  8. Let P=(x,0)P = (x, 0). (x−2)2=x2+36(x - 2)^2 = x^2 + 36, so x2−4x+4=x2+36x^2 - 4x + 4 = x^2 + 36, −4x=32-4x = 32, x=−8x = -8. P=(−8,0)P = (-8, 0).
  9. (5,4)(5, 4), (7,7)(7, 7), (4,7)(4, 7).
  10. In any tri­an­gle the ver­tex oppo­site the mid­point DD sat­is­fies A=E+F−DA = E + F - D (the seg­ment EFEF is par­al­lel to and half of the side through DD, so DD, EE, FF and the oppo­site ver­tex form a par­al­lel­o­gram). A=(7+1−4,6+5−2)=(4,9)A = (7 + 1 - 4, 6 + 5 - 2) = (4, 9). Sim­i­larly B=D+F−E=(4+1−7,2+5−6)=(−2,1)B = D + F - E = (4 + 1 - 7, 2 + 5 - 6) = (-2, 1) and C=D+E−F=(4+7−1,2+6−5)=(10,3)C = D + E - F = (4 + 7 - 1, 2 + 6 - 5) = (10, 3). Check: mid­point of BCBC is (4,2)=D(4, 2) = D ✓.
  11. Dis­tances from OO: 36+64=10\sqrt{36 + 64} = 10, 1010, 1010. Yes, radius 1010. (7,7)(7, 7) is 98≈9.9\sqrt{98} \approx 9.9 from OO: inside.
  12. First icon: left­most point 70−60=10>070 - 60 = 10 > 0, low­est 90−60=30>090 - 60 = 30 > 0: on screen. Sec­ond: 200−90=110>0200 - 90 = 110 > 0, 180−90=90>0180 - 90 = 90 > 0, and the far edges 290290 and 270270 are within 640640 and 480480: on screen. Cen­tres are 1302+902=16900+8100=25000≈158.1\sqrt{130^2 + 90^2} = \sqrt{16900 + 8100} = \sqrt{25000} \approx 158.1 apart; the radii add to 150<158.1150 < 158.1, so the icons do not over­lap.
A 640 by 480 screen with a circle of radius 60 centred at (70, 90) and a circle of radius 90 centred at (200, 180); the centres are about 158.1 apart and the circles do not touch.
The two icons of ques­tion 12 on the screen.
Triangle with vertices A(4, 9), B(-2, 1) and C(10, 3), and the dashed triangle joining the midpoints of its sides, D(4, 2), E(7, 6) and F(1, 5).
The tri­an­gle of ques­tion 10 rebuilt from its mid­points.