An expo­nent is a short way of writ­ing repeated mul­ti­pli­ca­tion. Instead of 2×2×2×2×2×2×2×2×2×22 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 we write 2102^{10}, which equals 1024. Expo­nents appear wher­ever quan­ti­ties grow or shrink by the same fac­tor again and again: com­pound inter­est, pop­u­la­tion growth, sci­en­tific nota­tion for very large and very small num­bers, and the prime fac­tori­sa­tions you will use in Class 10. Behind the large num­bers sits a small set of rules. Once you know them, and why they work, you can sim­plify long expres­sions in a few lines.

What exactly is an expo­nent?

Base and expo­nent

An expo­nent tells you how many times to mul­ti­ply a num­ber, the base, by itself. In the expres­sion ana^n:

  • aa is the base;
  • nn is the expo­nent (also called the power or index).

For a pos­i­tive inte­ger nn,

an=a×a××an factorsa^n = \underbrace{a \times a \times \cdots \times a}_{n \text{ factors}}

So 343^4 is not 3×43 \times 4. It is 3×3×3×33 \times 3 \times 3 \times 3, which equals 8181.

Read­ing pow­ers aloud

a2a^2 is read "aa squared", a3a^3 is "aa cubed", and ana^n is "aa to the power nn". Note that 32=(32)=9-3^2 = -(3^2) = -9, while (3)2=9(-3)^2 = 9: the expo­nent applies only to what sits directly below it.

The core expo­nent laws

The laws below hold for any non-zero bases aa and bb. We first see why each is true for pos­i­tive whole-num­ber expo­nents, where we can sim­ply count fac­tors. The def­i­n­i­tions of zero, neg­a­tive and frac­tional expo­nents later in the les­son are cho­sen so that the same laws keep work­ing.

1. The prod­uct rule

When you mul­ti­ply two pow­ers with the same base, add the expo­nents.

am×an=am+na^m \times a^n = a^{m+n}

Why it works: ama^m con­tributes mm fac­tors of aa and ana^n con­tributes nn more, so the prod­uct has m+nm + n fac­tors of aa.

Exam­ple: 23×24=(2×2×2)×(2×2×2×2)=27=1282^3 \times 2^4 = (2 \times 2 \times 2) \times (2 \times 2 \times 2 \times 2) = 2^7 = 128.

Tiles showing three 2s times four 2s making seven 2s, so 2^3 x 2^4 = 2^7 = 128; and six 5s over two 5s with two pairs struck out, leaving 5^4 = 625.
Count­ing fac­tors: mul­ti­ply­ing adds them, divid­ing can­cels them in pairs.

2. The quo­tient rule

When you divide two pow­ers with the same base, sub­tract the expo­nent of the denom­i­na­tor from the expo­nent of the numer­a­tor.

aman=amn\displaystyle \frac{a^m}{a^n} = a^{m-n}

Why it works: each fac­tor aa in the denom­i­na­tor can­cels one fac­tor aa in the numer­a­tor, so nn of the mm fac­tors dis­ap­pear.

Exam­ple: 5652=562=54=625\displaystyle \dfrac{5^6}{5^2} = 5^{6-2} = 5^4 = 625.

3. The power of a power rule

When a power is raised to another power, mul­ti­ply the expo­nents.

(am)n=amn(a^m)^n = a^{mn}

Why it works: (am)n(a^m)^n is nn copies of ama^m mul­ti­plied together, and each copy has mm fac­tors, giv­ing m×nm \times n fac­tors in all.

Exam­ple: (32)4=32×4=38=6561(3^2)^4 = 3^{2 \times 4} = 3^8 = 6561.

Han­dling dif­fer­ent bases and brack­ets

Some­times the base is a prod­uct or a quo­tient. The power then applies to each part.

4. The power of a prod­uct rule

(ab)n=an×bn(ab)^n = a^n \times b^n

Why it works: (ab)n=(ab)(ab)(ab)(ab)^n = (ab)(ab)\cdots(ab) with nn brack­ets. Rear­rang­ing gives nn fac­tors of aa and nn fac­tors of bb.

Exam­ple: (2x)3=23×x3=8x3(2x)^3 = 2^3 \times x^3 = 8x^3.

5. The power of a quo­tient rule

(ab)n=anbn\displaystyle \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n}

Exam­ple: (23)4=2434=1681\displaystyle \left(\dfrac{2}{3}\right)^4 = \dfrac{2^4}{3^4} = \dfrac{16}{81}.

The spe­cial cases: zero and neg­a­tive expo­nents

These are the rules that most often cause mis­takes in exams, yet they fol­low directly from the quo­tient rule.

6. The zero expo­nent rule

Any non-zero base raised to the power zero equals 1.

a0=1(a0)a^0 = 1 \quad (a \neq 0)

Why: by the quo­tient rule, 5252=522=50\displaystyle \dfrac{5^2}{5^2} = 5^{2-2} = 5^0. But any non-zero num­ber divided by itself is 1, so 505^0 must be 1. The expres­sion 000^0 is left unde­fined in school math­e­mat­ics.

7. The neg­a­tive expo­nent rule

A neg­a­tive expo­nent means "take the rec­i­p­ro­cal".

an=1an(a0)\displaystyle a^{-n} = \frac{1}{a^n} \quad (a \neq 0)

Why: a0an=a0n=an\displaystyle \dfrac{a^0}{a^n} = a^{0-n} = a^{-n}, and a0an=1an\displaystyle \dfrac{a^0}{a^n} = \dfrac{1}{a^n}.

Exam­ple: 42=142=116\displaystyle 4^{-2} = \dfrac{1}{4^2} = \dfrac{1}{16}. A use­ful con­se­quence is (ab)n=(ba)n\displaystyle \left(\dfrac{a}{b}\right)^{-n} = \left(\dfrac{b}{a}\right)^{n}.

Graph of y = 2^x for x from -3 to 3 with points marked: 2^-3 = 1/8, 2^-2 = 1/4, 2^-1 = 1/2, 2^0 = 1, 2^1 = 2, 2^2 = 4 and 2^3 = 8.
The graph of y=2xy = 2^x: mov­ing one step left halves the value, which is why 20=12^0 = 1 and 21=12\displaystyle 2^{-1} = \frac{1}{2}.

Frac­tional (ratio­nal) expo­nents

8. The ratio­nal expo­nent rule

When the expo­nent is a frac­tion, it describes a root. The denom­i­na­tor of the frac­tion is the index of the root. For a pos­i­tive base aa,

amn=amn=(an)m\displaystyle a^{\frac{m}{n}} = \sqrt[n]{a^m} = \left(\sqrt[n]{a}\right)^m

Why: by the power of a power rule, (a1n)n=ann=a1=a\displaystyle \left(a^{\frac{1}{n}}\right)^n = a^{\frac{n}{n}} = a^1 = a. So a1n\displaystyle a^{\frac{1}{n}} is the num­ber whose nnth power is aa, which is exactly an\sqrt[n]{a}.

Exam­ple: 912=9=3\displaystyle 9^{\frac{1}{2}} = \sqrt{9} = 3.

Exam­ple: 823=(83)2=22=4\displaystyle 8^{\frac{2}{3}} = \left(\sqrt[3]{8}\right)^2 = 2^2 = 4.

Tak­ing the root first, as here, keeps the num­bers small.

A method for sim­pli­fy­ing any expres­sion

  1. Write every num­ber as a power of a prime (for exam­ple 8=238 = 2^3, 27=3327 = 3^3, 81=3481 = 3^4).
  2. Remove brack­ets using the power of a prod­uct, power of a quo­tient and power of a power rules.
  3. Col­lect pow­ers of the same base using the prod­uct and quo­tient rules.
  4. Turn any neg­a­tive expo­nents into rec­i­p­ro­cals at the end, and eval­u­ate.

Worked exam­ples

Exam­ple 1: com­bin­ing rules with one base

Sim­plify 25×23÷212^5 \times 2^{-3} \div 2^{-1}.

25×23÷21=25+(3)(1)=23=8\begin{aligned} 2^5 \times 2^{-3} \div 2^{-1} &= 2^{5 + (-3) - (-1)} \\ &= 2^{3} \\ &= 8 \end{aligned}

Exam­ple 2: alge­braic bases

Sim­plify (x3y2)4x5y3\displaystyle \dfrac{(x^3y^2)^4}{x^5y^3}.

(x3y2)4x5y3=x12y8x5y3=x125y83=x7y5\displaystyle \begin{aligned} \frac{(x^3y^2)^4}{x^5y^3} &= \frac{x^{12}y^{8}}{x^5y^3} \\ &= x^{12-5}\,y^{8-3} \\ &= x^7y^5 \end{aligned}

Exam­ple 3: a neg­a­tive frac­tional expo­nent

Eval­u­ate (278)23\displaystyle \left(\dfrac{27}{8}\right)^{-\frac{2}{3}}.

(278)23=(827)23=(2333)23=2232=49\displaystyle \begin{aligned} \left(\frac{27}{8}\right)^{-\frac{2}{3}} &= \left(\frac{8}{27}\right)^{\frac{2}{3}} = \left(\frac{2^3}{3^3}\right)^{\frac{2}{3}} \\ &= \frac{2^{2}}{3^{2}} = \frac{4}{9} \end{aligned}

Exam­ple 4: neg­a­tive expo­nents inside a sum

Eval­u­ate (31+21)1\left(3^{-1} + 2^{-1}\right)^{-1}. The laws do not apply to a sum, so work out the bracket first.

(31+21)1=(13+12)1=(56)1=65\displaystyle \begin{aligned} \left(3^{-1} + 2^{-1}\right)^{-1} &= \left(\frac{1}{3} + \frac{1}{2}\right)^{-1} = \left(\frac{5}{6}\right)^{-1} \\ &= \frac{6}{5} \end{aligned}

Exam­ple 5: mixed bases

Eval­u­ate 2532×8114\displaystyle 25^{\frac{3}{2}} \times 81^{-\frac{1}{4}}.

2532×8114=(52)32×(34)14=53×31=1253\displaystyle \begin{aligned} 25^{\frac{3}{2}} \times 81^{-\frac{1}{4}} &= (5^2)^{\frac{3}{2}} \times (3^4)^{-\frac{1}{4}} \\ &= 5^3 \times 3^{-1} \\ &= \frac{125}{3} \end{aligned}

Exam­ple 6: solv­ing for an unknown expo­nent

Solve 2x+1=322^{x+1} = 32.

Write 32 as a power of 2: 32=2532 = 2^5. If two pow­ers of the same base (other than 0, 1 or 1-1) are equal, their expo­nents are equal.

2x+1=25x+1=5x=4\begin{aligned} 2^{x+1} &= 2^5 \\ x + 1 &= 5 \\ x &= 4 \end{aligned}

Sum­mary table for quick ref­er­ence

Rule For­mula Exam­ple
Prod­uct am×an=am+na^m \times a^n = a^{m+n} x2×x3=x5x^2 \times x^3 = x^5
Quo­tient am÷an=amna^m \div a^n = a^{m-n} y5÷y2=y3y^5 \div y^2 = y^3
Power of a power (am)n=amn(a^m)^n = a^{mn} (23)2=26=64(2^3)^2 = 2^6 = 64
Power of a prod­uct (ab)n=anbn(ab)^n = a^nb^n (2x)3=8x3(2x)^3 = 8x^3
Power of a quo­tient (ab)n=anbn\displaystyle \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} (23)4=1681\displaystyle \left(\frac{2}{3}\right)^4 = \frac{16}{81}
Zero power a0=1a^0 = 1 1,000,0000=11{,}000{,}000^0 = 1
Neg­a­tive power an=1an\displaystyle a^{-n} = \frac{1}{a^n} 32=19\displaystyle 3^{-2} = \frac{1}{9}
Frac­tional power a1n=an\displaystyle a^{\frac{1}{n}} = \sqrt[n]{a} 1614=2\displaystyle 16^{\frac{1}{4}} = 2

Com­mon mis­takes

  • Using the laws when the bases are dif­fer­ent. 23×322^3 \times 3^2 is not 656^5; work each power out sep­a­rately: 8×9=728 \times 9 = 72.
  • Mul­ti­ply­ing the base by the expo­nent: 343^4 is 8181, not 1212.
  • Adding expo­nents in a sum: 23+24=8+16=242^3 + 2^4 = 8 + 16 = 24, which is not 272^7. The prod­uct rule is for prod­ucts only.
  • Think­ing a neg­a­tive expo­nent makes a num­ber neg­a­tive: 42=116\displaystyle 4^{-2} = \frac{1}{16}, which is pos­i­tive.
  • Writ­ing a0=0a^0 = 0. For any non-zero aa, a0=1a^0 = 1.
  • For­get­ting brack­ets: 32=9-3^2 = -9 but (3)2=9(-3)^2 = 9, and 2x32x^3 means 2×x32 \times x^3, not (2x)3(2x)^3.

Try these

  1. Sim­plify 53×555^3 \times 5^{-5}. Answer: 125\displaystyle \frac{1}{25}
  2. Sim­plify (a2b1)3(a^2b^{-1})^3. Answer: a6b3\displaystyle \frac{a^6}{b^3}
  3. Eval­u­ate 1634\displaystyle 16^{\frac{3}{4}}. Answer: 88
  4. Eval­u­ate (12)3\displaystyle \left(\frac{1}{2}\right)^{-3}. Answer: 88
  5. Solve 32x1=273^{2x-1} = 27. Answer: x=2x = 2
  6. Eval­u­ate 3225\displaystyle 32^{-\frac{2}{5}}. Answer: 14\displaystyle \frac{1}{4}

Key terms

Base
The num­ber or expres­sion being mul­ti­plied repeat­edly; in ana^n it is aa.
Expo­nent (power, index)
The num­ber that says how many times the base is used as a fac­tor; in ana^n it is nn.
Power
The whole expres­sion ana^n, or its value.
Rec­i­p­ro­cal
The num­ber that mul­ti­plies with a given non-zero num­ber to give 1; the rec­i­p­ro­cal of ana^n is ana^{-n}.
Ratio­nal expo­nent
An expo­nent that is a frac­tion, such as 23\displaystyle \frac{2}{3}; it com­bines a power and a root.
nnth root
For a pos­i­tive num­ber aa, the pos­i­tive num­ber whose nnth power is aa, writ­ten an\sqrt[n]{a} or a1n\displaystyle a^{\frac{1}{n}}.
Expo­nen­tial growth
Growth by the same fac­tor in each step, as in 1,2,4,8,1, 2, 4, 8, \ldots, described by pow­ers such as 2x2^x.

Com­mon ques­tions

Why is any num­ber to the power zero equal to 1?

Because the quo­tient rule must keep work­ing. anan\displaystyle \frac{a^n}{a^n} is 1 for any non-zero aa, and the quo­tient rule says it is also ann=a0a^{n-n} = a^0. So a0a^0 has to be 1.

Can I add expo­nents when the bases are dif­fer­ent?

No. The prod­uct and quo­tient rules need the same base. If the expo­nents are equal you can com­bine the bases instead, as in 23×53=(2×5)3=10002^3 \times 5^3 = (2 \times 5)^3 = 1000.

What is the dif­fer­ence between ana^{-n} and an-a^n?

ana^{-n} is the rec­i­p­ro­cal 1an\displaystyle \frac{1}{a^n}, while an-a^n is the neg­a­tive of ana^n. For exam­ple, 23=18\displaystyle 2^{-3} = \frac{1}{8} but 23=8-2^3 = -8.

Should I take the root or the power first in amn\displaystyle a^{\frac{m}{n}}?

Both give the same answer for a pos­i­tive base, but tak­ing the root first keeps the num­bers small: 823=(83)2=4\displaystyle 8^{\frac{2}{3}} = (\sqrt[3]{8})^2 = 4 is eas­ier than 643=4\sqrt[3]{64} = 4.

Where are expo­nents used in Class 10?

In the Real Num­bers chap­ter, every num­ber is writ­ten as a prod­uct of prime pow­ers, and the HCF and LCM are found by com­par­ing expo­nents. Expo­nents also appear in sci­en­tific nota­tion and in com­pound inter­est.

Ref­er­ences

  1. National Coun­cil of Edu­ca­tional Research and Train­ing. Math­e­mat­ics: Text­book for Class X. NCERT, New Delhi.
  2. Gelfand, I. M. and Shen, A. Alge­bra. Birkhäuser.
  3. Stew­art, J., Redlin, L. and Wat­son, S. Pre­cal­cu­lus: Math­e­mat­ics for Cal­cu­lus. Cen­gage Learn­ing.

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