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Mathematics

Laws of Exponents: Exponent Rules and Formulas with Examples

Learn the laws of exponents, from the product, quotient and power rules to zero, negative and fractional powers, with the reason behind each rule, six worked examples and the mistakes to avoid.

Updated 8 min read

An expo­nent is a short way of writ­ing repeated mul­ti­pli­ca­tion. Instead of 2×2×2×2×2×2×2×2×2×22 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 we write 2102^{10}, which equals 1024. Expo­nents appear wher­ever quan­ti­ties grow or shrink by the same fac­tor again and again: com­pound inter­est, pop­u­la­tion growth, sci­en­tific nota­tion for very large and very small num­bers, and the prime fac­tori­sa­tions you will use in Class 10. Behind the large num­bers sits a small set of rules. Once you know them, and why they work, you can sim­plify long expres­sions in a few lines.

What exactly is an expo­nent?

Base and expo­nent

An expo­nent tells you how many times to mul­ti­ply a num­ber, the base, by itself. In the expres­sion ana^n:

  • aa is the base;
  • nn is the expo­nent (also called the power or index).

For a pos­i­tive inte­ger nn,

an=a×a×⋯×a⏟n factorsa^n = \underbrace{a \times a \times \cdots \times a}_{n \text{ factors}}

So 343^4 is not 3×43 \times 4. It is 3×3×3×33 \times 3 \times 3 \times 3, which equals 8181.

Read­ing pow­ers aloud

a2a^2 is read "aa squared", a3a^3 is "aa cubed", and ana^n is "aa to the power nn". Note that −32=−(32)=−9-3^2 = -(3^2) = -9, while (−3)2=9(-3)^2 = 9: the expo­nent applies only to what sits directly below it.

The core expo­nent laws

The laws below hold for any non-zero bases aa and bb. We first see why each is true for pos­i­tive whole-num­ber expo­nents, where we can sim­ply count fac­tors. The def­i­n­i­tions of zero, neg­a­tive and frac­tional expo­nents later in the les­son are cho­sen so that the same laws keep work­ing.

1. The prod­uct rule

When you mul­ti­ply two pow­ers with the same base, add the expo­nents.

am×an=am+na^m \times a^n = a^{m+n}

Why it works: ama^m con­tributes mm fac­tors of aa and ana^n con­tributes nn more, so the prod­uct has m+nm + n fac­tors of aa.

Exam­ple: 23×24=(2×2×2)×(2×2×2×2)=27=1282^3 \times 2^4 = (2 \times 2 \times 2) \times (2 \times 2 \times 2 \times 2) = 2^7 = 128.

Tiles showing three 2s times four 2s making seven 2s, so 2^3 x 2^4 = 2^7 = 128; and six 5s over two 5s with two pairs struck out, leaving 5^4 = 625.
Count­ing fac­tors: mul­ti­ply­ing adds them, divid­ing can­cels them in pairs.

2. The quo­tient rule

When you divide two pow­ers with the same base, sub­tract the expo­nent of the denom­i­na­tor from the expo­nent of the numer­a­tor.

aman=am−n\displaystyle \frac{a^m}{a^n} = a^{m-n}

Why it works: each fac­tor aa in the denom­i­na­tor can­cels one fac­tor aa in the numer­a­tor, so nn of the mm fac­tors dis­ap­pear.

Exam­ple: 5652=56−2=54=625\displaystyle \frac{5^6}{5^2} = 5^{6-2} = 5^4 = 625.

3. The power of a power rule

When a power is raised to another power, mul­ti­ply the expo­nents.

(am)n=amn(a^m)^n = a^{mn}

Why it works: (am)n(a^m)^n is nn copies of ama^m mul­ti­plied together, and each copy has mm fac­tors, giv­ing m×nm \times n fac­tors in all.

Exam­ple: (32)4=32×4=38=6561(3^2)^4 = 3^{2 \times 4} = 3^8 = 6561.

Han­dling dif­fer­ent bases and brack­ets

Some­times the base is a prod­uct or a quo­tient. The power then applies to each part.

4. The power of a prod­uct rule

(ab)n=an×bn(ab)^n = a^n \times b^n

Why it works: (ab)n=(ab)(ab)⋯(ab)(ab)^n = (ab)(ab)\cdots(ab) with nn brack­ets. Rear­rang­ing gives nn fac­tors of aa and nn fac­tors of bb.

Exam­ple: (2x)3=23×x3=8x3(2x)^3 = 2^3 \times x^3 = 8x^3.

5. The power of a quo­tient rule

(ab)n=anbn\displaystyle \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n}

Exam­ple: (23)4=2434=1681\displaystyle \left(\frac{2}{3}\right)^4 = \frac{2^4}{3^4} = \frac{16}{81}.

The spe­cial cases: zero and neg­a­tive expo­nents

These are the rules that most often cause mis­takes in exams, yet they fol­low directly from the quo­tient rule.

6. The zero expo­nent rule

Any non-zero base raised to the power zero equals 1.

a0=1(a≠0)a^0 = 1 \quad (a \neq 0)

Why: by the quo­tient rule, 5252=52−2=50\displaystyle \frac{5^2}{5^2} = 5^{2-2} = 5^0. But any non-zero num­ber divided by itself is 1, so 505^0 must be 1. The expres­sion 000^0 is left unde­fined in school math­e­mat­ics.

7. The neg­a­tive expo­nent rule

A neg­a­tive expo­nent means "take the rec­i­p­ro­cal".

a−n=1an(a≠0)\displaystyle a^{-n} = \frac{1}{a^n} \quad (a \neq 0)

Why: a0an=a0−n=a−n\displaystyle \frac{a^0}{a^n} = a^{0-n} = a^{-n}, and a0an=1an\displaystyle \frac{a^0}{a^n} = \frac{1}{a^n}.

Exam­ple: 4−2=142=116\displaystyle 4^{-2} = \frac{1}{4^2} = \frac{1}{16}. A use­ful con­se­quence is (ab)−n=(ba)n\displaystyle \left(\frac{a}{b}\right)^{-n} = \left(\frac{b}{a}\right)^{n}.

Graph of y = 2^x for x from -3 to 3 with points marked: 2^-3 = 1/8, 2^-2 = 1/4, 2^-1 = 1/2, 2^0 = 1, 2^1 = 2, 2^2 = 4 and 2^3 = 8.
The graph of y=2xy = 2^x: mov­ing one step left halves the value, which is why 20=12^0 = 1 and 2−1=12\displaystyle 2^{-1} = \frac{1}{2}.

Frac­tional (ratio­nal) expo­nents

8. The ratio­nal expo­nent rule

When the expo­nent is a frac­tion, it describes a root. The denom­i­na­tor of the frac­tion is the index of the root. For a pos­i­tive base aa,

amn=amn=(an)m\displaystyle a^{\frac{m}{n}} = \sqrt[n]{a^m} = \left(\sqrt[n]{a}\right)^m

Why: by the power of a power rule, (a1n)n=ann=a1=a\displaystyle \left(a^{\frac{1}{n}}\right)^n = a^{\frac{n}{n}} = a^1 = a. So a1n\displaystyle a^{\frac{1}{n}} is the num­ber whose nnth power is aa, which is exactly an\sqrt[n]{a}.

Exam­ple: 912=9=3\displaystyle 9^{\frac{1}{2}} = \sqrt{9} = 3.

Exam­ple: 823=(83)2=22=4\displaystyle 8^{\frac{2}{3}} = \left(\sqrt[3]{8}\right)^2 = 2^2 = 4.

Tak­ing the root first, as here, keeps the num­bers small.

A method for sim­pli­fy­ing any expres­sion

  1. Write every num­ber as a power of a prime (for exam­ple 8=238 = 2^3, 27=3327 = 3^3, 81=3481 = 3^4).
  2. Remove brack­ets using the power of a prod­uct, power of a quo­tient and power of a power rules.
  3. Col­lect pow­ers of the same base using the prod­uct and quo­tient rules.
  4. Turn any neg­a­tive expo­nents into rec­i­p­ro­cals at the end, and eval­u­ate.

Worked exam­ples

Exam­ple 1: com­bin­ing rules with one base

Sim­plify 25×2−3÷2−12^5 \times 2^{-3} \div 2^{-1}.

25×2−3÷2−1=25+(−3)−(−1)=23=8\begin{aligned} 2^5 \times 2^{-3} \div 2^{-1} &= 2^{5 + (-3) - (-1)} \\ &= 2^{3} \\ &= 8 \end{aligned}

Exam­ple 2: alge­braic bases

Sim­plify (x3y2)4x5y3\displaystyle \frac{(x^3y^2)^4}{x^5y^3}.

(x3y2)4x5y3=x12y8x5y3=x12−5 y8−3=x7y5\displaystyle \begin{aligned} \frac{(x^3y^2)^4}{x^5y^3} &= \frac{x^{12}y^{8}}{x^5y^3} \\ &= x^{12-5}\,y^{8-3} \\ &= x^7y^5 \end{aligned}

Exam­ple 3: a neg­a­tive frac­tional expo­nent

Eval­u­ate (278)−23\displaystyle \left(\frac{27}{8}\right)^{-\frac{2}{3}}.

(278)−23=(827)23=(2333)23=2232=49\displaystyle \begin{aligned} \left(\frac{27}{8}\right)^{-\frac{2}{3}} &= \left(\frac{8}{27}\right)^{\frac{2}{3}} = \left(\frac{2^3}{3^3}\right)^{\frac{2}{3}} \\ &= \frac{2^{2}}{3^{2}} = \frac{4}{9} \end{aligned}

Exam­ple 4: neg­a­tive expo­nents inside a sum

Eval­u­ate (3−1+2−1)−1\left(3^{-1} + 2^{-1}\right)^{-1}. The laws do not apply to a sum, so work out the bracket first.

(3−1+2−1)−1=(13+12)−1=(56)−1=65\displaystyle \begin{aligned} \left(3^{-1} + 2^{-1}\right)^{-1} &= \left(\frac{1}{3} + \frac{1}{2}\right)^{-1} = \left(\frac{5}{6}\right)^{-1} \\ &= \frac{6}{5} \end{aligned}

Exam­ple 5: mixed bases

Eval­u­ate 2532×81−14\displaystyle 25^{\frac{3}{2}} \times 81^{-\frac{1}{4}}.

2532×81−14=(52)32×(34)−14=53×3−1=1253\displaystyle \begin{aligned} 25^{\frac{3}{2}} \times 81^{-\frac{1}{4}} &= (5^2)^{\frac{3}{2}} \times (3^4)^{-\frac{1}{4}} \\ &= 5^3 \times 3^{-1} \\ &= \frac{125}{3} \end{aligned}

Exam­ple 6: solv­ing for an unknown expo­nent

Solve 2x+1=322^{x+1} = 32.

Write 32 as a power of 2: 32=2532 = 2^5. If two pow­ers of the same base (other than 0, 1 or −1-1) are equal, their expo­nents are equal.

2x+1=25x+1=5x=4\begin{aligned} 2^{x+1} &= 2^5 \\ x + 1 &= 5 \\ x &= 4 \end{aligned}

Sum­mary table for quick ref­er­ence

Rule For­mula Exam­ple
Prod­uct am×an=am+na^m \times a^n = a^{m+n} x2×x3=x5x^2 \times x^3 = x^5
Quo­tient am÷an=am−na^m \div a^n = a^{m-n} y5÷y2=y3y^5 \div y^2 = y^3
Power of a power (am)n=amn(a^m)^n = a^{mn} (23)2=26=64(2^3)^2 = 2^6 = 64
Power of a prod­uct (ab)n=anbn(ab)^n = a^nb^n (2x)3=8x3(2x)^3 = 8x^3
Power of a quo­tient (ab)n=anbn\displaystyle \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} (23)4=1681\displaystyle \left(\frac{2}{3}\right)^4 = \frac{16}{81}
Zero power a0=1a^0 = 1 1,000,0000=11{,}000{,}000^0 = 1
Neg­a­tive power a−n=1an\displaystyle a^{-n} = \frac{1}{a^n} 3−2=19\displaystyle 3^{-2} = \frac{1}{9}
Frac­tional power a1n=an\displaystyle a^{\frac{1}{n}} = \sqrt[n]{a} 1614=2\displaystyle 16^{\frac{1}{4}} = 2

Com­mon mis­takes

  • Using the laws when the bases are dif­fer­ent. 23×322^3 \times 3^2 is not 656^5; work each power out sep­a­rately: 8×9=728 \times 9 = 72.
  • Mul­ti­ply­ing the base by the expo­nent: 343^4 is 8181, not 1212.
  • Adding expo­nents in a sum: 23+24=8+16=242^3 + 2^4 = 8 + 16 = 24, which is not 272^7. The prod­uct rule is for prod­ucts only.
  • Think­ing a neg­a­tive expo­nent makes a num­ber neg­a­tive: 4−2=116\displaystyle 4^{-2} = \frac{1}{16}, which is pos­i­tive.
  • Writ­ing a0=0a^0 = 0. For any non-zero aa, a0=1a^0 = 1.
  • For­get­ting brack­ets: −32=−9-3^2 = -9 but (−3)2=9(-3)^2 = 9, and 2x32x^3 means 2×x32 \times x^3, not (2x)3(2x)^3.

Try these

  1. Sim­plify 53×5−55^3 \times 5^{-5}. Answer: 125\displaystyle \frac{1}{25}
  2. Sim­plify (a2b−1)3(a^2b^{-1})^3. Answer: a6b3\displaystyle \frac{a^6}{b^3}
  3. Eval­u­ate 1634\displaystyle 16^{\frac{3}{4}}. Answer: 88
  4. Eval­u­ate (12)−3\displaystyle \left(\frac{1}{2}\right)^{-3}. Answer: 88
  5. Solve 32x−1=273^{2x-1} = 27. Answer: x=2x = 2
  6. Eval­u­ate 32−25\displaystyle 32^{-\frac{2}{5}}. Answer: 14\displaystyle \frac{1}{4}

Key terms

Base
The num­ber or expres­sion being mul­ti­plied repeat­edly; in ana^n it is aa.
Expo­nent (power, index)
The num­ber that says how many times the base is used as a fac­tor; in ana^n it is nn.
Power
The whole expres­sion ana^n, or its value.
Rec­i­p­ro­cal
The num­ber that mul­ti­plies with a given non-zero num­ber to give 1; the rec­i­p­ro­cal of ana^n is a−na^{-n}.
Ratio­nal expo­nent
An expo­nent that is a frac­tion, such as 23\displaystyle \frac{2}{3}; it com­bines a power and a root.
nnth root
For a pos­i­tive num­ber aa, the pos­i­tive num­ber whose nnth power is aa, writ­ten an\sqrt[n]{a} or a1n\displaystyle a^{\frac{1}{n}}.
Expo­nen­tial growth
Growth by the same fac­tor in each step, as in 1,2,4,8,…1, 2, 4, 8, \ldots, described by pow­ers such as 2x2^x.

Com­mon ques­tions

Why is any num­ber to the power zero equal to 1?

Because the quo­tient rule must keep work­ing. anan\displaystyle \frac{a^n}{a^n} is 1 for any non-zero aa, and the quo­tient rule says it is also an−n=a0a^{n-n} = a^0. So a0a^0 has to be 1.

Can I add expo­nents when the bases are dif­fer­ent?

No. The prod­uct and quo­tient rules need the same base. If the expo­nents are equal you can com­bine the bases instead, as in 23×53=(2×5)3=10002^3 \times 5^3 = (2 \times 5)^3 = 1000.

What is the dif­fer­ence between a−na^{-n} and −an-a^n?

a−na^{-n} is the rec­i­p­ro­cal 1an\displaystyle \frac{1}{a^n}, while −an-a^n is the neg­a­tive of ana^n. For exam­ple, 2−3=18\displaystyle 2^{-3} = \frac{1}{8} but −23=−8-2^3 = -8.

Should I take the root or the power first in amn\displaystyle a^{\frac{m}{n}}?

Both give the same answer for a pos­i­tive base, but tak­ing the root first keeps the num­bers small: 823=(83)2=4\displaystyle 8^{\frac{2}{3}} = (\sqrt[3]{8})^2 = 4 is eas­ier than 643=4\sqrt[3]{64} = 4.

Where are expo­nents used in Class 10?

In the Real Num­bers chap­ter, every num­ber is writ­ten as a prod­uct of prime pow­ers, and the HCF and LCM are found by com­par­ing expo­nents. Expo­nents also appear in sci­en­tific nota­tion and in com­pound inter­est.

Ref­er­ences

  1. National Coun­cil of Edu­ca­tional Research and Train­ing. Math­e­mat­ics: Text­book for Class X. NCERT, New Delhi.
  2. Gelfand, I. M. and Shen, A. Alge­bra. Birkhäuser.
  3. Stew­art, J., Redlin, L. and Wat­son, S. Pre­cal­cu­lus: Math­e­mat­ics for Cal­cu­lus. Cen­gage Learn­ing.