Think of a sequence as numbers standing in a queue, in a fixed order. Add them up and you have a series. We will first see two ways of describing a sequence, by a formula or by a rule that builds each term from the ones before it. Then we spend most of our time on the friendliest kind, the arithmetic progression, where you keep adding the same amount: its general term, the sum of n terms, and the arithmetic mean.
A sequence is a function on N: a1,a2,a3,…, with an the general term. You can describe it by a formula, so an=n2−1 gives 0,3,8,15,…, or recursively, so a1=2, an+1=3an−1 gives 2,5,14,41,… The famous Fibonacci sequence is recursive too: a1=a2=1, an+2=an+1+an.
In an AP you move by a constant common differenced: a,a+d,a+2d,…
an=a+(n−1)d,Sn=2n[2a+(n−1)d]=2n(a+l),
where l is the last term. Where does the sum formula come from? Write Sn forwards, then backwards underneath, and add the two lines. Every pair adds up to the same thing, a+l, and that is the whole trick.
A handy fact: if you add, subtract, multiply or divide every term by the same constant, you still have an AP.
Example 1. In the AP 7,11,15,…: a20=7+19×4=83; S20=10(7+83)=900.
Example 1: the AP 7, 11, 15, ... moves in equal steps of 4
Example 2. Which term of 5,12,19,… is 278? Set the general term equal to it: 5+7(n−1)=278, so n=40.
Example 3. Suppose the 4th term is 13 and the 11th is 41. Subtracting, 7d=28, d=4, a=1; an=4n−3.
Example 4. How many terms of −12,−9,−6,… do you need for the sum to reach 54? 2n(−24+3(n−1))=54 gives n2−9n−36=0, n=12 (the negative root makes no sense for a count of terms, so we drop it).
Example 5. Find the sum of the integers from 1 to 300 divisible by 3 or 7. Take the multiples of 3 first: 100 terms, sum 15,150. Multiples of 7: 42 terms, sum 6,321. But multiples of 21 got counted twice: 14 terms, sum 2,205. So the answer is 15,150+6,321−2,205=19,266.
The AM of a and b is 2a+b, the number sitting exactly halfway, so that a,A,b is an AP. If you want to insert n numbers between a and b making an AP, take d=n+1b−a.
Example 6. Insert 5 numbers between 4 and 28. Here d=4, so we get 8,12,16,20,24.
Example 6: five numbers inserted between 4 and 28 make an AP