Expresswala Academy Mathematics Tuition

Basic Mathematical Operations

Question paper, Set 6

  • Set 6 of 10
  • 20 questions
  • 50 marks
  • 1 hour 30 minutes

Download the PDF (with key sheet and solutions, 66.3 KB)

Work each question on paper first, then open its answer and solution to check your work.

  1. Find (i) 2+62 + 6 (ii) 6−16 - 1.
    1 mark
    Answer and solution

    (i) Start at 66 and count on 22: 2+6=82 + 6 = 8

    (ii) Count back 11 from 66: 6−1=56 - 1 = 5

    Answer: (i) 88 (ii) 55

  2. Fill in the box and find the sum: 7+7=10+□7 + 7 = 10 + \square.
    2 marks
    Answer and solution

    77 needs 33 to make 1010; take 33 from 77, which leaves 44.

    7+7=10+4=147 + 7 = 10 + 4 = 14

    Answer: □=4\square = 4; 7+7=147 + 7 = 14

  3. Find the number in the box: 1+□=51 + \square = 5.
    1 mark
    Answer and solution

    □=5−1=4\square = 5 - 1 = 4

    Check: 1+4=51 + 4 = 5

    Answer: 44

  4. Find (i) 80−980 - 9 (ii) 40−340 - 3.
    2 marks
    Answer and solution

    (i) 80=70+1080 = 70 + 10 and 10−9=110 - 9 = 1, so 80−9=70+1=7180 - 9 = 70 + 1 = 71

    (ii) 40=30+1040 = 30 + 10 and 10−3=710 - 3 = 7, so 40−3=30+7=3740 - 3 = 30 + 7 = 37

    Answer: (i) 7171 (ii) 3737

  5. Find 44−444 - 4.
    1 mark
    Answer and solution

    Take 44 from the units digit: 4−4=04 - 4 = 0; the tens digit 44 stays.

    44−4=4044 - 4 = 40

    Answer: 4040

  6. Find 13−613 - 6 by the 1st and 2nd methods.
    2 marks
    Answer and solution

    1st method: take 33 out of 66 first (6−3=36 - 3 = 3): 13−6=10−3=713 - 6 = 10 - 3 = 7

    2nd method: add 44 to both: 13−6=17−10=713 - 6 = 17 - 10 = 7

    Both methods give 13−6=713 - 6 = 7

    Answer: 77

  7. Find 93−893 - 8 by three methods.
    3 marks
    Answer and solution

    1st method: take 33 out of 88 first (8−3=58 - 3 = 5): 93−8=90−5=8593 - 8 = 90 - 5 = 85

    2nd method: add 22 to both: 93−8=95−10=8593 - 8 = 95 - 10 = 85

    3rd method: 93−10=8393 - 10 = 83 and 10−8=210 - 8 = 2, so 93−8=83+2=8593 - 8 = 83 + 2 = 85

    All three methods give 93−8=8593 - 8 = 85

    Answer: 8585

  8. Find 85−5085 - 50.
    1 mark
    Answer and solution

    Take 55 tens from 88 tens: 8−5=38 - 5 = 3; the units digit 55 stays.

    85−50=3585 - 50 = 35

    Answer: 3535

  9. Find 82−5882 - 58 by four methods.
    5 marks
    Answer and solution

    1st method (take the tens first): 82−58=32−8=30−6=2482 - 58 = 32 - 8 = 30 - 6 = 24

    2nd method: add 22 to both: 82−58=84−60=2482 - 58 = 84 - 60 = 24

    3rd method: 82−60=2282 - 60 = 22 and 60−58=260 - 58 = 2, so 82−58=22+2=2482 - 58 = 22 + 2 = 24

    4th method (column): 2<82 < 8, so borrow 11 ten: units 12−8=412 - 8 = 4, tens 7−5=27 - 5 = 2

    All four methods give 82−58=2482 - 58 = 24

    Answer: 2424

  10. Find (i) 170−5170 - 5 (ii) 459−16459 - 16.
    2 marks
    Answer and solution

    (i) 170=160+10170 = 160 + 10 and 10−5=510 - 5 = 5, so 170−5=160+5=165170 - 5 = 160 + 5 = 165

    (ii) units 9−6=39 - 6 = 3, tens 5−1=45 - 1 = 4, hundreds 44 stays: 459−16=443459 - 16 = 443

    Answer: (i) 165165 (ii) 443443

  11. Find 470−33470 - 33 by four methods.
    5 marks
    Answer and solution

    1st method (take the tens first): 470−33=440−3=437470 - 33 = 440 - 3 = 437

    2nd method: add 77 to both: 470−33=477−40=437470 - 33 = 477 - 40 = 437

    3rd method: 470−40=430470 - 40 = 430 and 40−33=740 - 33 = 7, so 470−33=430+7=437470 - 33 = 430 + 7 = 437

    4th method (column): 0<30 < 3, so borrow 11 ten: units 10−3=710 - 3 = 7, tens 6−3=36 - 3 = 3, hundreds 44

    All four methods give 470−33=437470 - 33 = 437

    Answer: 437437

  12. Find 100−11100 - 11.
    2 marks
    Answer and solution

    Take away the tens first: 100−10=90100 - 10 = 90

    100−11=90−1=89100 - 11 = 90 - 1 = 89

    Answer: 8989

  13. Find 181−88181 - 88 by three methods.
    5 marks
    Answer and solution

    1st method (column): units 1<81 < 8, borrow 11 ten: 11−8=311 - 8 = 3

    tens: 7<87 < 8, borrow from the hundred: 17−8=917 - 8 = 9, hundreds 00

    2nd method: take 11 from both: 181−88=180−87181 - 88 = 180 - 87

    take 8080 from both: =100−7=93= 100 - 7 = 93

    3rd method: 181−100=81181 - 100 = 81 and 100−88=12100 - 88 = 12, so 181−88=81+12=93181 - 88 = 81 + 12 = 93

    All three methods give 181−88=93181 - 88 = 93

    Answer: 9393

  14. Find 20+1520 + 15.
    1 mark
    Answer and solution

    Add the tens: 20+10=3020 + 10 = 30; the units digit 55 stays.

    20+15=3520 + 15 = 35

    Answer: 3535

  15. Find 65+7465 + 74 by adding the tens and then the units.
    2 marks
    Answer and solution

    Tens: 60+70=13060 + 70 = 130

    Units: 5+4=95 + 4 = 9

    65+74=130+9=13965 + 74 = 130 + 9 = 139

    Answer: 139139

  16. Find 4986÷94986 \div 9 by long division.
    3 marks
    Answer and solution

    49÷949 \div 9: 9×5=459 \times 5 = 45, 49−45=449 - 45 = 4

    Bring down 88, we have 4848: 9×5=459 \times 5 = 45, 48−45=348 - 45 = 3

    Bring down 66, we have 3636: 9×4=369 \times 4 = 36, 36−36=036 - 36 = 0

    Remainder 00, so 4986÷9=5544986 \div 9 = 554

    Answer: 554554

  17. Find 7550250÷57550250 \div 5 by long division.
    5 marks
    Answer and solution

    7÷57 \div 5: 5×1=55 \times 1 = 5, 7−5=27 - 5 = 2

    Bring down 55, we have 2525: 5×5=255 \times 5 = 25, 25−25=025 - 25 = 0

    Bring down 55, we have 55: 5×1=55 \times 1 = 5, 5−5=05 - 5 = 0

    Bring down 00, we have 00: 0<50 < 5, so write 00 in the quotient

    Bring down 22, we have 22: 2<52 < 5, so write 00 in the quotient

    Bring down 55, we have 2525: 5×5=255 \times 5 = 25, 25−25=025 - 25 = 0

    Bring down 00, we have 00: 0<50 < 5, so write 00 in the quotient

    Remainder 00, so 7550250÷5=15100507550250 \div 5 = 1510050

    Answer: 15100501510050

  18. Find 27405÷927405 \div 9 by long division.
    3 marks
    Answer and solution

    27÷927 \div 9: 9×3=279 \times 3 = 27, 27−27=027 - 27 = 0

    Bring down 44, we have 44: 4<94 < 9, so write 00 in the quotient

    Bring down 00, we have 4040: 9×4=369 \times 4 = 36, 40−36=440 - 36 = 4

    Bring down 55, we have 4545: 9×5=459 \times 5 = 45, 45−45=045 - 45 = 0

    Remainder 00, so 27405÷9=304527405 \div 9 = 3045

    Do not miss the 00 in the quotient.

    Answer: 30453045

  19. Find 9852÷129852 \div 12 by long division.
    3 marks
    Answer and solution

    98÷1298 \div 12: 12×8=9612 \times 8 = 96, 98−96=298 - 96 = 2

    Bring down 55, we have 2525: 12×2=2412 \times 2 = 24, 25−24=125 - 24 = 1

    Bring down 22, we have 1212: 12×1=1212 \times 1 = 12, 12−12=012 - 12 = 0

    Remainder 00, so 9852÷12=8219852 \div 12 = 821

    Answer: 821821

  20. Find 355\displaystyle \frac{35}{5}.
    1 mark
    Answer and solution

    355\displaystyle \frac{35}{5} means 35÷535 \div 5.

    5×7=355 \times 7 = 35, so 355=7\displaystyle \frac{35}{5} = 7

    Answer: 77