Basic Mathematical Operations: MCQ test, Set 8

$9 - 5 =$
A $5$ B $4$ C $14$ D $3$

Answer and solution

Answer: (B) $4$

Count back $5$ from $9$ .

$9 - 5 = 4$
$2 + \square = 6$ . The number in the box is
A $4$ B $5$ C $3$ D $8$

Answer and solution

Answer: (A) $4$

$\square = 6 - 2 = 4$

Check: $2 + 4 = 6$
On the number line, start at $60$ and jump back $5$ steps. You land on
A $54$ B $55$ C $56$ D $65$

Answer and solution

Answer: (B) $55$

Jumping back $5$ steps from $60$ means $60 - 5$ .

$60 = 50 + 10$ and $10 - 5 = 5$ , so $60 - 5 = 50 + 5 = 55$
$65 - 4 =$
A $25$ B $60$ C $69$ D $61$

Answer and solution

Answer: (D) $61$

Take $4$ from the units digit: $5 - 4 = 1$ ; the tens digit $6$ stays.

$65 - 4 = 61$
$69 - 6 =$
A $75$ B $62$ C $63$ D $64$

Answer and solution

Answer: (C) $63$

Take $6$ from the units digit: $9 - 6 = 3$ ; the tens digit $6$ stays.

$69 - 6 = 63$
By the 2nd method, $77 - 9 = \square - 10$ . The number in the box is
A $78$ B $68$ C $76$ D $86$

Answer and solution

Answer: (A) $78$

2nd method: add $1$ to both: $77 - 9 = 78 - 10 = 68$

So the box is $78$
$83 - 9 =$
A $74$ B $86$ C $92$ D $84$

Answer and solution

Answer: (A) $74$

1st method: take $3$ out of $9$ first ( $9 - 3 = 6$ ): $83 - 9 = 80 - 6 = 74$
$57 - 10 =$
A $56$ B $47$ C $57$ D $67$

Answer and solution

Answer: (B) $47$

Take $1$ ten from $5$ tens: $5 - 1 = 4$ ; the units digit $7$ stays.

$57 - 10 = 47$
By the 2nd method, $72 - 33 = \square - 40$ . The number in the box is
A $75$ B $65$ C $79$ D $39$

Answer and solution

Answer: (C) $79$

Add $7$ to both numbers so that $33$ becomes $40$ .

$72 - 33 = 79 - 40$ , so the box is $79$
$68 - 57 =$
A $125$ B $12$ C $21$ D $11$

Answer and solution

Answer: (D) $11$

units $8 - 7 = 1$ , tens $6 - 5 = 1$ : $68 - 57 = 11$
$220 - 5 =$
A $214$ B $215$ C $216$ D $225$

Answer and solution

Answer: (B) $215$

$220 = 210 + 10$ and $10 - 5 = 5$ , so $220 - 5 = 210 + 5 = 215$
$190 - 41 =$
A $159$ B $231$ C $149$ D $151$

Answer and solution

Answer: (C) $149$

2nd method: add $9$ to both: $190 - 41 = 199 - 50 = 149$
$100 - 53 = \square - 3$ . The number in the box is
A $47$ B $40$ C $60$ D $50$

Answer and solution

Answer: (D) $50$

Take away the tens first: $100 - 50 = 50$

So $100 - 53 = 50 - 3$ ; the box is $50$
$100 - 76 =$
A $23$ B $36$ C $34$ D $24$

Answer and solution

Answer: (D) $24$

Take away the tens first: $100 - 70 = 30$

$100 - 76 = 30 - 6 = 24$
$130 - 90 =$
A $160$ B $40$ C $140$ D $220$

Answer and solution

Answer: (B) $40$

Take $30$ from both: $130 - 90 = 100 - 60$

$100 - 60 = 40$
$134 - 49 =$
A $95$ B $185$ C $85$ D $115$

Answer and solution

Answer: (C) $85$

3rd method: $134 - 100 = 34$ and $100 - 49 = 51$

$134 - 49 = 34 + 51 = 85$
$30 + 35 =$
A $55$ B $38$ C $65$ D $75$

Answer and solution

Answer: (C) $65$

Add the tens: $30 + 30 = 60$ ; the units digit $5$ stays.

$30 + 35 = 65$
$60 + 20 =$
A $80$ B $90$ C $70$ D $8$

Answer and solution

Answer: (A) $80$

$6$ tens $+$ $2$ tens $=$ $8$ tens

$60 + 20 = 80$
$81 + 51 =$
A $32$ B $122$ C $132$ D $142$

Answer and solution

Answer: (C) $132$

Tens: $80 + 50 = 130$

Units: $1 + 1 = 2$

$81 + 51 = 130 + 2 = 132$
In $1712 \div 8$ , the first step is $17 \div 8$ . The remainder after this step is
A $1$ B $7$ C $9$ D $2$

Answer and solution

Answer: (A) $1$

$8 \times 2 = 16$ is the biggest number in the $8$ table that is not more than $17$ .

$17 - 16 = 1$
$3072 \div 6 =$
A $513$ B $5012$ C $502$ D $512$

Answer and solution

Answer: (D) $512$

Long division with the $6$ table gives $512$ .

Check: $6 \times 512 = 3072$
$768414 \div 2 =$
A $384207$ B $384208$ C $38427$ D $3084207$

Answer and solution

Answer: (A) $384207$

Divide digit by digit with the $2$ table: $768414 \div 2 = 384207$

Check: $2 \times 384207 = 768414$
$20510 \div 5 =$
A $4102$ B $4120$ C $412$ D $41002$

Answer and solution

Answer: (A) $4102$

When a brought-down number is less than $5$ , a $0$ goes in the quotient.

$20510 \div 5 = 4102$ (check: $5 \times 4102 = 20510$ )
$6996 \div 12 =$
A $584$ B $583$ C $582$ D $5083$

Answer and solution

Answer: (B) $583$

Long division with the $12$ table gives $583$ .

Check: $12 \times 583 = 6996$
$\displaystyle \frac{20}{5} =$
A $5$ B $100$ C $15$ D $4$

Answer and solution

Answer: (D) $4$

$\displaystyle \frac{20}{5}$ means $20 \div 5$ .

$5 \times 4 = 20$ , so $\displaystyle \frac{20}{5} = 4$

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MCQ test, Set 8