Basic Mathematical Operations: MCQ test, Set 7

$2 + 2 =$
A $4$ B $3$ C $5$ D $6$

Answer and solution

Answer: (A) $4$

Start at $2$ and count on $2$ : $2 + 2 = 4$
$6 + \square = 7$ . The number in the box is
A $7$ B $2$ C $13$ D $1$

Answer and solution

Answer: (D) $1$

$\square = 7 - 6 = 1$

Check: $6 + 1 = 7$
$90 - 9 =$
A $99$ B $82$ C $81$ D $91$

Answer and solution

Answer: (C) $81$

$90 = 80 + 10$ and $10 - 9 = 1$ , so $90 - 9 = 80 + 1 = 81$
$48 - 4 =$
A $43$ B $45$ C $44$ D $52$

Answer and solution

Answer: (C) $44$

Take $4$ from the units digit: $8 - 4 = 4$ ; the tens digit $4$ stays.

$48 - 4 = 44$
$23 - 3 =$
A $20$ B $19$ C $26$ D $21$

Answer and solution

Answer: (A) $20$

Take $3$ from the units digit: $3 - 3 = 0$ ; the tens digit $2$ stays.

$23 - 3 = 20$
$27 - 9 =$
A $22$ B $18$ C $36$ D $28$

Answer and solution

Answer: (B) $18$

1st method: take $7$ out of $9$ first ( $9 - 7 = 2$ ): $27 - 9 = 20 - 2 = 18$
By the 2nd method, $26 - 9 = \square - 10$ . The number in the box is
A $17$ B $25$ C $27$ D $35$

Answer and solution

Answer: (C) $27$

2nd method: add $1$ to both: $26 - 9 = 27 - 10 = 17$

So the box is $27$
$80 - 40 =$
A $40$ B $30$ C $120$ D $50$

Answer and solution

Answer: (A) $40$

$8$ tens $-$ $4$ tens $=$ $4$ tens

$80 - 40 = 40$
$61 - 24 =$
A $43$ B $85$ C $47$ D $37$

Answer and solution

Answer: (D) $37$

2nd method: add $6$ to both: $61 - 24 = 67 - 30 = 37$
$87 - 13 =$
A $100$ B $75$ C $84$ D $74$

Answer and solution

Answer: (D) $74$

units $7 - 3 = 4$ , tens $8 - 1 = 7$ : $87 - 13 = 74$
$373 - 38 =$
A $345$ B $335$ C $411$ D $334$

Answer and solution

Answer: (B) $335$

2nd method: add $2$ to both: $373 - 38 = 375 - 40 = 335$
$410 - 5 =$
A $406$ B $404$ C $405$ D $415$

Answer and solution

Answer: (C) $405$

$410 = 400 + 10$ and $10 - 5 = 5$ , so $410 - 5 = 400 + 5 = 405$
$100 - 19 =$
A $91$ B $81$ C $80$ D $99$

Answer and solution

Answer: (B) $81$

Take away the tens first: $100 - 10 = 90$

$100 - 19 = 90 - 9 = 81$
$100 - 85 = \square - 5$ . The number in the box is
A $20$ B $10$ C $30$ D $15$

Answer and solution

Answer: (A) $20$

Take away the tens first: $100 - 80 = 20$

So $100 - 85 = 20 - 5$ ; the box is $20$
$101 - 4 =$
A $87$ B $103$ C $97$ D $98$

Answer and solution

Answer: (C) $97$

Take $1$ from both: $101 - 4 = 100 - 3$

$100 - 3 = 97$
$152 - 79 =$
A $83$ B $127$ C $173$ D $73$

Answer and solution

Answer: (D) $73$

3rd method: $152 - 100 = 52$ and $100 - 79 = 21$

$152 - 79 = 52 + 21 = 73$
$70 + 30 =$
A $110$ B $100$ C $10$ D $90$

Answer and solution

Answer: (B) $100$

$7$ tens $+$ $3$ tens $=$ $10$ tens

$70 + 30 = 100$
$90 + 43 =$
A $133$ B $123$ C $143$ D $52$

Answer and solution

Answer: (A) $133$

Add the tens: $90 + 40 = 130$ ; the units digit $3$ stays.

$90 + 43 = 133$
$72 + 24 =$
A $86$ B $96$ C $97$ D $106$

Answer and solution

Answer: (B) $96$

Tens: $70 + 20 = 90$

Units: $2 + 4 = 6$

$72 + 24 = 90 + 6 = 96$
$1448 \div 2 =$
A $724$ B $725$ C $714$ D $7024$

Answer and solution

Answer: (A) $724$

Long division with the $2$ table gives $724$ .

Check: $2 \times 724 = 1448$
In $1776 \div 8$ , the first step is $17 \div 8$ . The remainder after this step is
A $2$ B $9$ C $1$ D $7$

Answer and solution

Answer: (C) $1$

$8 \times 2 = 16$ is the biggest number in the $8$ table that is not more than $17$ .

$17 - 16 = 1$
$413626 \div 2 =$
A $206814$ B $2006813$ C $206813$ D $26813$

Answer and solution

Answer: (C) $206813$

Divide digit by digit with the $2$ table: $413626 \div 2 = 206813$

Check: $2 \times 206813 = 413626$
$8688 \div 8 =$
A $1860$ B $186$ C $10086$ D $1086$

Answer and solution

Answer: (D) $1086$

When a brought-down number is less than $8$ , a $0$ goes in the quotient.

$8688 \div 8 = 1086$ (check: $8 \times 1086 = 8688$ )
$4236 \div 12 =$
A $3053$ B $353$ C $352$ D $354$

Answer and solution

Answer: (B) $353$

Long division with the $12$ table gives $353$ .

Check: $12 \times 353 = 4236$
$\displaystyle \frac{14}{2} =$
A $8$ B $12$ C $28$ D $7$

Answer and solution

Answer: (D) $7$

$\displaystyle \frac{14}{2}$ means $14 \div 2$ .

$2 \times 7 = 14$ , so $\displaystyle \frac{14}{2} = 7$

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MCQ test, Set 7