Once the axioms are in place, the everyday rules for "or" and "not" follow almost for free. Add the counting you learnt in permutations and combinations, and questions about cards and committees become straightforward probability sums. We will prove the addition rule and the complement rule, use them on real questions, and end with a mixed practice set on the whole chapter.
Complement.P(A′)=1−P(A). This holds because A and A′ are mutually exclusive and exhaustive. It is often far easier to find the chance of something not happening and subtract it from one.
Addition rule. For any two events,
P(A∪B)=P(A)+P(B)−P(A∩B).
Why subtract? Because A∪B is the disjoint union of A and B−A, and P(B−A)=P(B)−P(A∩B). When the events are mutually exclusive, the last term is simply 0.
"But not".P(A−B)=P(A)−P(A∩B).
Example 1. Suppose P(A)=0.54, P(B)=0.69 and P(A∩B)=0.35. Then P(A∪B)=0.88; P(A′∩B′)=P((A∪B)′)=0.12; P(A∩B′)=0.19.
Example 1: the probabilities of the four regions
Example 2. A card is drawn from a pack. The king of hearts must not be counted twice, so P(king or heart)=524+5213−521=134.
Example 3. Draw 4 cards from a pack. P(all four are aces)=52C41=270,7251. And P(exactly two hearts)=52C413C239C2=270,72578×741≈0.213.
Example 4. A committee of 3 is chosen from 5 men and 4 women. "At least one" is a signal to use the complement: P(at least one woman)=1−9C35C3=1−8410=4237.
Example 5. The letters of ASSIST are arranged at random. Tie the three S's together as one block, and P(the three S’s are together)=6!/3!4!/1=12024=51.
Example 6. A number is chosen from 1 to 100. Numbers divisible by both are counted twice, so take them out once: P(divisible by 4 or 6)=10025+16−8=10033.
Example 6: 25 + 16 - 8 = 33 numbers are divisible by 4 or 6
In a class of 60, 30 play football, 32 play cricket and 24 play both. A student is chosen at random. Find P(plays neither) and P(plays exactly one).
From a group of 6 boys and 4 girls, 3 are chosen at random. Find P(exactly 2 girls) and P(at least 1 girl).
A bag has 5 red, 4 blue and 3 green balls. Two are drawn. Find P(same colour).
In a lottery a person picks 6 numbers from 1 to 20. Six numbers are drawn at random. What is the chance of winning, that is, of all six matching?
5 boys and 3 girls sit in a row at random. Find P(the girls are all together).
Given P(A)=53 and P(B)=51, find P(A∪B) if A and B are mutually exclusive.
A number is chosen from the 4-digit numbers formed by 1,2,3,4,5 without repetition. Find P(it is divisible by 5) and P(it is even).
Could P(A)=0.6, P(B)=0.5, P(A∩B)=0.05 all be true? Explain.
Out of 50 tickets numbered 1–50, one is drawn. Find P(it is a multiple of 3 or a square).