Expresswala Academy Mathematics Tuition

Arithmetic Applications (Level 1)

MCQ test, Set 3

  • Set 3 of 10
  • 25 questions
  • 25 marks
  • 30 minutes

Download the PDF (with key sheet and solutions, 89.8 KB)

Choose one answer for each question, then check your score at the end. Each correct answer carries 1 mark; there is no negative marking.

  1. Find the ratio of the price of coffee to that of tea, when coffee costs ₹45 per 100 g and tea costs ₹600 per kg.
    Answer and solution

    Answer: (B) 3:43 : 4

    100 g of coffee costs ₹45, so 1000 g (1 kg) costs ₹450.

    Required ratio=450600=34=3:4\displaystyle \text{Required ratio} = \frac{450}{600} = \frac{3}{4} = 3 : 4

  2. If ₹1440 is divided into two parts in the ratio 7:97 : 9, then the smaller part is
    Answer and solution

    Answer: (B) ₹630

    Smaller part=77+9×1440=716×1440=630\displaystyle \text{Smaller part} = \frac{7}{7 + 9} \times 1440 = \frac{7}{16} \times 1440 = 630

  3. The ratio of boys to girls in a school with 720 students is 7:57 : 5. If 30 more girls are admitted, the new ratio of boys to girls is
    Answer and solution

    Answer: (D) 14:1114 : 11

    Boys=712×720=420,Girls=720−420=300\displaystyle \text{Boys} = \frac{7}{12} \times 720 = 420, \quad \text{Girls} = 720 - 420 = 300

    New ratio=420330=14:11\displaystyle \text{New ratio} = \frac{420}{330} = 14 : 11

  4. In the proportion 3:5::12:203 : 5 :: 12 : 20, the means are
    Answer and solution

    Answer: (C) 55 and 1212

    In a:b::c:da : b :: c : d, the second and third terms are the means.

    So the means are 55 and 1212 (and 5×12=60=3×205 \times 12 = 60 = 3 \times 20).

  5. If 16, xx, xx, 25 are in proportion, then x=x =
    Answer and solution

    Answer: (C) 2020

    16x=x25⇒x2=400⇒x=20\displaystyle \frac{16}{x} = \frac{x}{25} \Rightarrow x^2 = 400 \Rightarrow x = 20

  6. If a:b=c:da : b = c : d, then a+ba−b=c+dc−d\displaystyle \frac{a+b}{a-b} = \frac{c+d}{c-d}. This property is called
    Answer and solution

    Answer: (D) Componendo and dividendo

    Adding (componendo) and subtracting (dividendo) together gives a+ba−b=c+dc−d\displaystyle \frac{a+b}{a-b} = \frac{c+d}{c-d}: componendo and dividendo.

  7. The cost of 8 m of cloth is ₹456. The cost of 5 m of the same cloth is (in ₹)
    Answer and solution

    Answer: (A) 285285

    Direct proportion: x1y2=x2y1x_1 y_2 = x_2 y_1

    y=5×4568=285\displaystyle y = \frac{5 \times 456}{8} = 285

  8. 12 pumps fill a tank in 45 minutes. If 3 pumps go out of order, the remaining pumps fill it in
    Answer and solution

    Answer: (B) 6060 minutes

    Inverse proportion: x1y1=x2y2x_1 y_1 = x_2 y_2

    12×45=9×y⇒y=6012 \times 45 = 9 \times y \Rightarrow y = 60

  9. 0.070.07 expressed as a percentage is
    Answer and solution

    Answer: (C) 7%7\%

    0.07=(0.07×100)%=7%0.07 = (0.07 \times 100)\% = 7\%

  10. What percent of 6 is 9?
    Answer and solution

    Answer: (B) 150%150\%

    (96×100)%=150%\displaystyle \left(\frac{9}{6} \times 100\right)\% = 150\%

  11. By what percent is 72 more than 60?
    Answer and solution

    Answer: (A) 20%20\%

    Change =12= 12

    (1260×100)%=20%\displaystyle \left(\frac{12}{60} \times 100\right)\% = 20\%

    Always divide by the original value.

  12. The price of tea rises by 20%20\%. To keep the expenditure the same, consumption must be reduced by
    Answer and solution

    Answer: (D) 1623%\displaystyle 16\frac{2}{3}\%

    (20100+20×100)%=(20120×100)%=1623%\displaystyle \left(\frac{20}{100 + 20} \times 100\right)\% = \left(\frac{20}{120} \times 100\right)\% = 16\frac{2}{3}\%

  13. A population of 10000 increases at 10%10\% per annum. After 3 years it will be
    Answer and solution

    Answer: (A) 13,31013{,}310

    10000(1110)3=13310\displaystyle 10000\left(\frac{11}{10}\right)^3 = 13310

  14. An agent gets 2%2\% commission on his sales. If his commission is ₹350, the goods sold are worth
    Answer and solution

    Answer: (D) ₹17,500

    2100x=350⇒x=350×1002=17500\displaystyle \frac{2}{100}x = 350 \Rightarrow x = \frac{350 \times 100}{2} = 17500

  15. The cost price of an article is ₹480 and the markup is 35%35\%. Its marked price is
    Answer and solution

    Answer: (A) ₹648

    M.P=480+35100×480=480+168=648\displaystyle \text{M.P} = 480 + \frac{35}{100} \times 480 = 480 + 168 = 648

  16. Two chairs are sold at ₹1500 each, one at 25%25\% profit and the other at 25%25\% loss. On the whole there is a
    Answer and solution

    Answer: (C) loss of 6.25%6.25\%

    Same S.P, a%a\% profit and a%a\% loss: always a loss of (a10)2%\displaystyle \left(\frac{a}{10}\right)^2\%.

    (2510)2=6.25%\displaystyle \left(\frac{25}{10}\right)^2 = 6.25\%

  17. If the cost price of 24 articles equals the selling price of 18 articles, then there is a
    Answer and solution

    Answer: (C) 3313%\displaystyle 33\frac{1}{3}\% gain

    24x=18y⇒yx=43\displaystyle 24x = 18y \Rightarrow \frac{y}{x} = \frac{4}{3}

    (yx−1)×100=3313%\displaystyle \left(\frac{y}{x} - 1\right) \times 100 = 33\frac{1}{3}\% (a gain)

  18. The average of 9 numbers is 42. The average of the first 4 is 40 and that of the last 4 is 45. The 5th number is
    Answer and solution

    Answer: (B) 3838

    Sum of 9 =378= 378, first 4 =160= 160, last 4 =180= 180

    x5=378−160−180=38x_5 = 378 - 160 - 180 = 38

  19. The average of x1,x2,…,xnx_1, x_2, \ldots, x_n is 12. The average of 2x1+5,2x2+5,…,2xn+52x_1 + 5, 2x_2 + 5, \ldots, 2x_n + 5 is
    Answer and solution

    Answer: (D) 2929

    Average of axi+bax_i + b is axˉ+b=2(12)+5=29a\bar{x} + b = 2(12) + 5 = 29

  20. If a man travels at 40 km/h, he reaches his destination 12 minutes late, and at 60 km/h he reaches 8 minutes early. The distance travelled is
    Answer and solution

    Answer: (A) 4040 km

    Let TT be the correct time (hours): D=40(T+1260)=60(T−860)\displaystyle D = 40\left(T + \frac{12}{60}\right) = 60\left(T - \frac{8}{60}\right)

    ⇒T=45 h,D=40×1=40 km\displaystyle \Rightarrow T = \frac{4}{5} \text{ h}, \quad D = 40 \times 1 = 40 \text{ km}

  21. A cyclist covers three equal distances at 20 km/h, 30 km/h and 60 km/h. His average speed is
    Answer and solution

    Answer: (A) 3030 km/h

    3×20×30×60600+1800+1200=1,08,0003600=30\displaystyle \frac{3 \times 20 \times 30 \times 60}{600 + 1800 + 1200} = \frac{1{,}08{,}000}{3600} = 30

  22. The speeds of two trains are in the ratio 4:54 : 5. The first takes 10 hours for a journey. The second takes
    Answer and solution

    Answer: (C) 88 hours

    s1:s2=T2:T1⇒4:5=T2:10s_1 : s_2 = T_2 : T_1 \Rightarrow 4 : 5 = T_2 : 10

    T2=4×105=8\displaystyle T_2 = \frac{4 \times 10}{5} = 8 hours

  23. Two trains are moving in the same direction at 68 km/h and 50 km/h. Their relative speed is
    Answer and solution

    Answer: (B) 1818 km/h

    Same direction: relative speed =(x−y)=68−50=18= (x - y) = 68 - 50 = 18 km/h

  24. The simple interest on ₹1250 for 4 years is ₹300. The rate of interest per annum is
    Answer and solution

    Answer: (D) 6%6\%

    R=300×1001250×4=6%\displaystyle R = \frac{300 \times 100}{1250 \times 4} = 6\%

  25. The amount on ₹8000 at 10%10\% per annum for 1 year, compounded half-yearly, is
    Answer and solution

    Answer: (D) ₹8820

    k=2k = 2: A=8000(1+10200)2=8000×2120×2120=8820\displaystyle A = 8000\left(1 + \frac{10}{200}\right)^2 = 8000 \times \frac{21}{20} \times \frac{21}{20} = 8820