"I am think­ing of a num­ber. When I add 2 to it, I get 8. What is my num­ber?" You can prob­a­bly answer at once: 6. In alge­bra this puz­zle is writ­ten as x+2=8x + 2 = 8, and find­ing xx is called solv­ing the equa­tion. In this les­son you learn a sure method for equa­tions like this, where a num­ber is added to xx or taken away from it, includ­ing equa­tions whose answers are neg­a­tive inte­gers.

What an equa­tion is

An equa­tion is a state­ment that two amounts are equal. It has an equals sign, a left side and a right side.

x+2=8x + 2 = 8

Here the left side is x+2x + 2 and the right side is 8. The let­ter xx stands for a num­ber we do not know yet.

To solve an equa­tion means to find the value of xx that makes both sides equal. That value is called the solu­tion.

Think of a bal­ance with two pans. The equals sign says the two pans weigh the same. If you take the same amount off both pans, they still bal­ance.

Equa­tions like x + a = b

Exam­ple 1

Solve x+2=8x + 2 = 8.

Two has been added to xx. To get xx on its own, take 2 away from both sides. The 2 dis­ap­pears from the left, and 8 becomes 8−28 - 2 on the right.

x+2=8⇒x=8−2⇒x=6\begin{aligned}x + 2 &= 8 \\ \Rightarrow x &= 8 - 2 \\ \Rightarrow x &= 6\end{aligned}

The arrow ⇒\Rightarrow is read "implies". It means "so the next line is true".

Check. Put 6 in place of xx: 6+2=86 + 2 = 8. Both sides are 8, so x=6x = 6 is right.

Look at what hap­pened to the 2. It was added on the left. It moved to the right side and became taken away. This is called trans­pos­ing.

Remem­ber. When a num­ber moves to the other side of the equals sign, its sign changes. Plus becomes minus, and minus becomes plus.

Exam­ple 2

Solve x+5=11x + 5 = 11.

x+5=11⇒x=11−5⇒x=6\begin{aligned}x + 5 &= 11 \\ \Rightarrow x &= 11 - 5 \\ \Rightarrow x &= 6\end{aligned}

Check: 6+5=116 + 5 = 11.

Exam­ple 3

Solve x+7=−8x + 7 = -8.

The +7+7 moves across and becomes −7-7.

x+7=−8⇒x=−8−7⇒x=−15\begin{aligned}x + 7 &= -8 \\ \Rightarrow x &= -8 - 7 \\ \Rightarrow x &= -15\end{aligned}

To work out −8−7-8 - 7, use the rule for adding inte­gers. Both signs are minus, so add 8+7=158 + 7 = 15 and keep the minus sign.

Check: −15+7=−8-15 + 7 = -8. The signs dif­fer, the dif­fer­ence is 8, and the big­ger num­ber, 15, is neg­a­tive. So both sides are −8-8.

Equa­tions like x − a = b

Now a num­ber is taken away from xx. To undo tak­ing away, add.

Exam­ple 4

Solve x−2=4x - 2 = 4.

The −2-2 moves across and becomes +2+2.

x−2=4⇒x=4+2⇒x=6\begin{aligned}x - 2 &= 4 \\ \Rightarrow x &= 4 + 2 \\ \Rightarrow x &= 6\end{aligned}

Check: 6−2=46 - 2 = 4.

Exam­ple 5

Solve x−8=−15x - 8 = -15.

x−8=−15⇒x=−15+8⇒x=−7\begin{aligned}x - 8 &= -15 \\ \Rightarrow x &= -15 + 8 \\ \Rightarrow x &= -7\end{aligned}

For −15+8-15 + 8 the signs are dif­fer­ent. The dif­fer­ence is 15−8=715 - 8 = 7, and the big­ger num­ber, 15, is neg­a­tive. So the answer is −7-7.

Check: −7−8=−15-7 - 8 = -15.

Exam­ple 6

Solve x−8=−2x - 8 = -2.

x−8=−2⇒x=−2+8⇒x=6\begin{aligned}x - 8 &= -2 \\ \Rightarrow x &= -2 + 8 \\ \Rightarrow x &= 6\end{aligned}

This time the big­ger num­ber, 8, is pos­i­tive, so the answer is pos­i­tive. Check: 6−8=−26 - 8 = -2.

Exam­ple 7

Solve x−15=−27x - 15 = -27.

x−15=−27⇒x=−27+15⇒x=−12\begin{aligned}x - 15 &= -27 \\ \Rightarrow x &= -27 + 15 \\ \Rightarrow x &= -12\end{aligned}

The dif­fer­ence is 27−15=1227 - 15 = 12, and 27 is the big­ger num­ber with a minus sign, so x=−12x = -12. Check: −12−15=−27-12 - 15 = -27.

The inte­ger facts you need

Every step above used the rules for adding inte­gers. Here they are again with small num­bers.

Sum Rule Answer
8+78 + 7 both pos­i­tive: add 1515
−8−7-8 - 7 both neg­a­tive: add, keep minus −15-15
−9+3-9 + 3 signs dif­fer: 9−39 - 3, sign of 9 −6-6
−9+12-9 + 12 signs dif­fer: 12−912 - 9, sign of 12 33

The two rules so far

Equa­tion Solu­tion
x+a=bx + a = b x=b−ax = b - a
x−a=bx - a = b x=b+ax = b + a

Remem­ber. Always check your answer by putting it back into the equa­tion. If both sides come out equal, the answer is right.

Com­mon mis­takes

  • For­get­ting to change the sign. In x+7=−8x + 7 = -8, the 7 moves across as −7-7, not +7+7.
  • Get­ting the inte­ger arith­metic wrong. −8−7-8 - 7 is −15-15, not −1-1.
  • Not check­ing. A quick check catches most slips.
  • Writ­ing the answer as a sum. Fin­ish the arith­metic: write x=6x = 6, not x=8−2x = 8 - 2.

Key terms

  • Equa­tion: a state­ment that two amounts are equal, such as x+2=8x + 2 = 8.
  • Solve: find the value of the let­ter that makes the equa­tion true.
  • Solu­tion: the value that makes the equa­tion true.
  • Trans­pose: move a term to the other side of the equals sign, chang­ing its sign.

Prac­tice

  1. Solve x+9=15x + 9 = 15.
  2. Solve x+125=256x + 125 = 256.
  3. Solve x+12=−28x + 12 = -28.
  4. Solve x+3=−3x + 3 = -3.
  5. Solve x−11=7x - 11 = 7.
  6. Solve x−19=32x - 19 = 32.
  7. Solve x−27=−45x - 27 = -45.
  8. Solve x−25=−10x - 25 = -10.
  9. Solve x−6=−6x - 6 = -6.
  10. Solve x+14=9x + 14 = 9.
  11. When 8 is added to a num­ber, the result is −3-3. Find the num­ber.
  12. Check whether x=−4x = -4 is the solu­tion of x−5=−9x - 5 = -9.

Answers

Show answers
  1. x=15−9=6x = 15 - 9 = 6
  2. x=256−125=131x = 256 - 125 = 131
  3. x=−28−12=−40x = -28 - 12 = -40
  4. x=−3−3=−6x = -3 - 3 = -6
  5. x=7+11=18x = 7 + 11 = 18
  6. x=32+19=51x = 32 + 19 = 51
  7. x=−45+27=−18x = -45 + 27 = -18
  8. x=−10+25=15x = -10 + 25 = 15
  9. x=−6+6=0x = -6 + 6 = 0
  10. x=9−14=−5x = 9 - 14 = -5
  11. x+8=−3x + 8 = -3, so x=−3−8=−11x = -3 - 8 = -11.
  12. Yes. −4−5=−9-4 - 5 = -9, so both sides are equal.