Expresswala Academy Mathematics Tuition

Cubes and Cube Roots

Question paper, Set 7

  • Set 7 of 10
  • 20 questions
  • 50 marks
  • 1 hour 30 minutes

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Work each question on paper first, then open its answer and solution to check your work.

  1. Write n3n^3 in words.
    1 mark
    Answer and solution

    n3=n×n×nn^3 = n \times n \times n

    It is read as 'nn power 3' (or) 'nn cubed'.

    Answer: nn power 3 (or) nn cubed

  2. Write b×b×b×c×c×cb \times b \times b \times c \times c \times c using cubes.
    2 marks
    Answer and solution

    b×b×b=b3b \times b \times b = b^3

    c×c×c=c3c \times c \times c = c^3

    ∴b×b×b×c×c×c=b3×c3\therefore b \times b \times b \times c \times c \times c = b^3 \times c^3

    Answer: b3×c3b^3 \times c^3

  3. Write the value of 333^3 from the table of cubes.
    1 mark
    Answer and solution

    33=3×3×33^3 = 3 \times 3 \times 3

    =9×3=27= 9 \times 3 = 27

    Answer: 2727

  4. 600 lies between the cubes of which two consecutive numbers?
    2 marks
    Answer and solution

    From the table: 83=5128^3 = 512 and 93=7299^3 = 729.

    512<600<729512 < 600 < 729

    So 600 lies between 838^3 and 939^3.

    Answer: Between 838^3 and 939^3

  5. Which of these numbers are cubes? Write each cube as the cube of a number: 8, 16, 216, 400, 512.
    3 marks
    Answer and solution

    Check each number with the table of cubes.

    23=82^3 = 8

    63=2166^3 = 216

    83=5128^3 = 512

    The other numbers are not in the table of cubes, so they are not cubes.

    Answer: 8=238 = 2^3, 216=63216 = 6^3, 512=83512 = 8^3

  6. Find the value of 13313^3.
    2 marks
    Answer and solution

    13×13=16913 \times 13 = 169

    133=169×13=219713^3 = 169 \times 13 = 2197

    Answer: 21972197

  7. Asha wrote 163=16×16=25616^3 = 16 \times 16 = 256. (i) What mistake did she make? (ii) Find the correct value of 16316^3 by first finding 16×1616 \times 16. (iii) In the same way, find 11311^3.
    5 marks
    Answer and solution

    (i) She multiplied 16 by itself only 2 times. 16316^3 needs 3 factors of 16.

    (ii) 16×16=25616 \times 16 = 256, 256×16=4096256 \times 16 = 4096

    (iii) 11×11=12111 \times 11 = 121, 121×11=1331121 \times 11 = 1331

    Answer: (ii) 163=409616^3 = 4096 (iii) 113=133111^3 = 1331

  8. Is (−25)3(-25)^3 a positive or a negative number? Explain without finding its value.
    1 mark
    Answer and solution

    (−25)3=−253(-25)^3 = -25^3

    The cube of a negative number is negative.

    Answer: Negative

  9. Find the values of (−7)3(-7)^3 and (−9)3(-9)^3.
    2 marks
    Answer and solution

    (−7)3=−73=−343(-7)^3 = -7^3 = -343

    9×9=819 \times 9 = 81, 81×9=72981 \times 9 = 729

    ∴(−9)3=−729\therefore (-9)^3 = -729

    Answer: (−7)3=−343(-7)^3 = -343, (−9)3=−729(-9)^3 = -729

  10. Find the cubes of −8-8, −10-10 and −12-12.
    3 marks
    Answer and solution

    (−8)3=−83=−(64×8)=−512(-8)^3 = -8^3 = -(64 \times 8) = -512

    (−10)3=−103=−(100×10)=−1000(-10)^3 = -10^3 = -(100 \times 10) = -1000

    (−12)3=−123=−(144×12)=−1728(-12)^3 = -12^3 = -(144 \times 12) = -1728

    Answer: (−8)3=−512(-8)^3 = -512, (−10)3=−1000(-10)^3 = -1000, (−12)3=−1728(-12)^3 = -1728

  11. Find 23+732^3 + 7^3.
    1 mark
    Answer and solution

    23+73=8+3432^3 + 7^3 = 8 + 343

    =351= 351

    Answer: 351351

  12. Find the sum of the cubes of the first 6 natural numbers.
    5 marks
    Answer and solution

    13+23+33+43+53+63=1+8+27+64+125+2161^3 + 2^3 + 3^3 + 4^3 + 5^3 + 6^3 = 1 + 8 + 27 + 64 + 125 + 216

    =441= 441

    Answer: 441441

  13. Find 93+(−9)39^3 + (-9)^3.
    1 mark
    Answer and solution

    (−9)3=−93(-9)^3 = -9^3

    93+(−9)3=93−93=09^3 + (-9)^3 = 9^3 - 9^3 = 0

    Answer: 00

  14. Find the value of 53+(−8)35^3 + (-8)^3.
    2 marks
    Answer and solution

    53+(−8)3=125+(−512)5^3 + (-8)^3 = 125 + (-512)

    =125−512= 125 - 512

    =−387= -387

    Answer: −387-387

  15. How much more is the cube of 10 than the cube of 7?
    2 marks
    Answer and solution

    Difference = 103−7310^3 - 7^3

    103−73=1000−34310^3 - 7^3 = 1000 - 343

    =657= 657

    Answer: 657657

  16. Find the value of 113−13311^3 - 13^3.
    3 marks
    Answer and solution

    113=121×11=133111^3 = 121 \times 11 = 1331

    133=169×13=219713^3 = 169 \times 13 = 2197

    113−133=1331−219711^3 - 13^3 = 1331 - 2197

    =−866= -866

    Answer: −866-866

  17. Kiran wrote: 113−143=(11−14)3=(−3)3=−2711^3 - 14^3 = (11 - 14)^3 = (-3)^3 = -27. (i) Find the correct value of 113−14311^3 - 14^3. (ii) What was Kiran's mistake?
    5 marks
    Answer and solution

    (i) 113=121×11=133111^3 = 121 \times 11 = 1331

    143=196×14=274414^3 = 196 \times 14 = 2744

    113−143=1331−2744=−141311^3 - 14^3 = 1331 - 2744 = -1413

    (ii) Each number must be cubed first and then subtracted. 113−14311^3 - 14^3 is not (11−14)3(11 - 14)^3.

    Answer: (i) −1413-1413 (ii) He subtracted the numbers before cubing them

  18. Simplify t3−(−t)3t^3 - (-t)^3.
    1 mark
    Answer and solution

    (−t)3=−t3(-t)^3 = -t^3

    t3−(−t3)=t3+t3=2t3t^3 - (-t^3) = t^3 + t^3 = 2t^3

    Answer: 2t32t^3

  19. Arrange in ascending order: (−4)3(-4)^3, 333^3, −23-2^3, (−5)3(-5)^3, 131^3.
    3 marks
    Answer and solution

    (−4)3=−64(-4)^3 = -64, 33=273^3 = 27, −23=−8-2^3 = -8, (−5)3=−125(-5)^3 = -125, 13=11^3 = 1

    −125<−64<−8<1<27-125 < -64 < -8 < 1 < 27

    So the order is (−5)3(-5)^3, (−4)3(-4)^3, −23-2^3, 131^3, 333^3.

    Answer: (−5)3(-5)^3, (−4)3(-4)^3, −23-2^3, 131^3, 333^3

  20. Simplify −63+(−2)3−(−5)3+33-6^3 + (-2)^3 - (-5)^3 + 3^3.
    5 marks
    Answer and solution

    −63+(−2)3−(−5)3+33=−216+(−8)−(−125)+27-6^3 + (-2)^3 - (-5)^3 + 3^3 = -216 + (-8) - (-125) + 27

    =−216−8+125+27= -216 - 8 + 125 + 27

    =−72= -72

    Answer: −72-72