Sur­face area tells us how much mate­r­ial cov­ers a solid. Vol­ume tells us how much space it takes up, and capac­ity how much a hol­low con­tainer can hold. Water tanks, grain bins, pipes and brick walls are all vol­ume prob­lems. This les­son gives the vol­umes of cuboids, cubes and cylin­ders, explains the units, and uses them in prac­ti­cal ques­tions.

Units of vol­ume and capac­ity

Vol­ume is mea­sured in cubic units: a cube of edge 11 cm has vol­ume 11 cm³.

1 m3=100×100×100 cm3=1000000 cm31 \text{ m}^3 = 100 \times 100 \times 100 \text{ cm}^3 = 1000000 \text{ cm}^3

Capac­ity is usu­ally given in litres:

1 litre=1000 cm3,1 m3=1000 litres1 \text{ litre} = 1000 \text{ cm}^3, \qquad 1 \text{ m}^3 = 1000 \text{ litres}

Cuboid and cube

Volume of cuboid=l×b×h,Volume of cube=a3\text{Volume of cuboid} = l \times b \times h, \qquad \text{Volume of cube} = a^3

Both come from the same idea: vol­ume == area of the base ×\times height.

Exam­ple 1

A water tank is 66 m long, 44 m wide and 2.52.5 m deep. How many litres can it hold?

Volume=6×4×2.5=60 m3=60×1000=60000 litres\text{Volume} = 6 \times 4 \times 2.5 = 60 \text{ m}^3 = 60 \times 1000 = 60000 \text{ litres}

Exam­ple 2

A cube has vol­ume 343343 cm³. Find its edge and its total sur­face area.

a3=343a^3 = 343, so a=7a = 7 cm. Total sur­face area =6×72=294= 6 \times 7^2 = 294 cm².

Exam­ple 3

A wall 1515 m long, 0.30.3 m thick and 44 m high is built of bricks mea­sur­ing 2525 cm by 1515 cm by 88 cm. How many bricks are needed (ignor­ing mor­tar)?

Work in metres. The brick is 0.250.25 m by 0.150.15 m by 0.080.08 m.

Volume of wall=15×0.3×4=18 m3\text{Volume of wall} = 15 \times 0.3 \times 4 = 18 \text{ m}^3

Volume of one brick=0.25×0.15×0.08=0.003 m3\text{Volume of one brick} = 0.25 \times 0.15 \times 0.08 = 0.003 \text{ m}^3

Number of bricks=180.003=6000\displaystyle \text{Number of bricks} = \frac{18}{0.003} = 6000

Always change all lengths to the same unit before mul­ti­ply­ing.

Cylin­der

A cylin­der also has vol­ume == base area ×\times height, and its base is a cir­cle:

Volume of cylinder=πr2h\text{Volume of cylinder} = \pi r^2 h

Exam­ple 4

Find the vol­ume of a cylin­der of radius 77 cm and height 1010 cm, and its capac­ity in litres.

V=227×7×7×10=1540 cm3=15401000=1.54 litres\displaystyle V = \frac{22}{7} \times 7 \times 7 \times 10 = 1540 \text{ cm}^3 = \frac{1540}{1000} = 1.54 \text{ litres}

Hol­low cylin­ders

A pipe is a hol­low cylin­der with outer radius RR and inner radius rr. The mate­r­ial in it is the big cylin­der minus the hole:

Volume of material=πR2h−πr2h=π(R2−r2)h\text{Volume of material} = \pi R^2 h - \pi r^2 h = \pi(R^2 - r^2)h

Exam­ple 5

A metal pipe is 7070 cm long, with outer radius 44 cm and inner radius 33 cm. Find the vol­ume of metal in it.

V=227×(16−9)×70=227×7×70=1540 cm3\displaystyle V = \frac{22}{7} \times (16 - 9) \times 70 = \frac{22}{7} \times 7 \times 70 = 1540 \text{ cm}^3

Exam­ple 6

The vol­ume of a cylin­der is 92409240 cm³ and its height is 1515 cm. Find its radius.

227×r2×15=9240  ⟹  r2=9240×722×15=196  ⟹  r=14 cm\displaystyle \frac{22}{7} \times r^2 \times 15 = 9240 \implies r^2 = \frac{9240 \times 7}{22 \times 15} = 196 \implies r = 14 \text{ cm}

Prac­tice

  1. Find the vol­ume of a cuboid 1212 cm by 88 cm by 55 cm.
  2. Find the vol­ume of a cube of edge 99 cm.
  3. A tank is 44 m long, 33 m wide and 22 m deep. How many litres does it hold?
  4. Find the vol­ume of a cylin­der of radius 1414 cm and height 1515 cm.
  5. A cylin­der has vol­ume 15401540 cm³ and height 1010 cm. Find its radius.
  6. A hol­low cylin­der is 1414 cm long, with outer radius 1010 cm and inner radius 88 cm. Find the vol­ume of mate­r­ial in it.
  7. A wall 1212 m long, 2020 cm thick and 33 m high is built of bricks 2424 cm by 1010 cm by 88 cm. How many bricks are needed?
  8. A cylin­dri­cal tank has diam­e­ter 2.82.8 m and height 55 m. Find its capac­ity in litres.

Answers

Show answers
  1. 12×8×5=48012 \times 8 \times 5 = 480 cm³
  2. 93=7299^3 = 729 cm³
  3. 4×3×2=244 \times 3 \times 2 = 24 m³ =24000= 24000 litres
  4. 227×196×15=9240\displaystyle \frac{22}{7} \times 196 \times 15 = 9240 cm³
  5. 227×r2×10=1540\displaystyle \frac{22}{7} \times r^2 \times 10 = 1540, so r2=49r^2 = 49 and r=7r = 7 cm.
  6. 227×(100−64)×14=22×36×2=1584\displaystyle \frac{22}{7} \times (100 - 64) \times 14 = 22 \times 36 \times 2 = 1584 cm³
  7. Wall 12×0.2×3=7.212 \times 0.2 \times 3 = 7.2 m³; brick 0.24×0.1×0.08=0.001920.24 \times 0.1 \times 0.08 = 0.00192 m³; 7.20.00192=3750\displaystyle \frac{7.2}{0.00192} = 3750 bricks.
  8. r=1.4r = 1.4 m: 227×1.96×5=30.8\displaystyle \frac{22}{7} \times 1.96 \times 5 = 30.8 m³ =30800= 30800 litres