How do you tell a friend exactly where a seat is in a cin­ema? You give a row and a seat num­ber: two num­bers fix one place. Coor­di­nate geom­e­try does the same for points on a flat sur­face. Two per­pen­dic­u­lar num­ber lines turn every point into a pair of num­bers, and that lets us solve geom­e­try prob­lems with alge­bra. This les­son sets up the sys­tem, intro­duced by the French math­e­mati­cian René Descartes, which is why it is called the Carte­sian plane.

The axes and the ori­gin

Draw a hor­i­zon­tal num­ber line and a ver­ti­cal num­ber line cross­ing at their zero points.

  • The hor­i­zon­tal line is the x-axis. Num­bers to the right of zero are pos­i­tive, to the left neg­a­tive.
  • The ver­ti­cal line is the y-axis. Num­bers above zero are pos­i­tive, below neg­a­tive.
  • The cross­ing point is the ori­gin, OO.

The two axes divide the plane into four regions called quad­rants, num­bered anti­clock­wise start­ing from the top right.

Coor­di­nates of a point

To describe a point PP, drop per­pen­dic­u­lars from PP to both axes. If the foot on the x-axis is at xx and the foot on the y-axis is at yy, the coor­di­nates of PP are the ordered pair (x,y)(x, y).

  • xx is the x-coor­di­nate or abscissa: the signed dis­tance of PP from the y-axis.
  • yy is the y-coor­di­nate or ordi­nate: the signed dis­tance of PP from the x-axis.

The ori­gin is (0,0)(0, 0). The order mat­ters: (2,5)(2, 5) is 22 to the right and 55 up, while (5,2)(5, 2) is a dif­fer­ent point, 55 to the right and 22 up.

To plot (−3,2)(-3, 2), start at the ori­gin, move 33 units left, then 22 units up, and mark the point.

Signs in the four quad­rants

Quad­rant Posi­tion Sign of xx Sign of yy Exam­ple
I top right ++ ++ (3,4)(3, 4)
II top left −- ++ (−2,5)(-2, 5)
III bot­tom left −- −- (−1,−7)(-1, -7)
IV bot­tom right ++ −- (3,−4)(3, -4)

Points on the axes belong to no quad­rant. Every point on the x-axis has y-coor­di­nate 00, so it looks like (a,0)(a, 0). Every point on the y-axis has x-coor­di­nate 00, so it looks like (0,b)(0, b).

Exam­ple 1

Where do these points lie? (3,−4)(3, -4), (−2,5)(-2, 5), (−1,−7)(-1, -7), (0,6)(0, 6), (4,0)(4, 0)

(3,−4)(3, -4) is in quad­rant IV, (−2,5)(-2, 5) in quad­rant II, (−1,−7)(-1, -7) in quad­rant III. (0,6)(0, 6) lies on the y-axis and (4,0)(4, 0) on the x-axis.

Exam­ple 2

How far is the point (−6,8)(-6, 8) from each axis?

Its dis­tance from the x-axis is the size of its y-coor­di­nate, 88 units. Its dis­tance from the y-axis is the size of its x-coor­di­nate, 66 units. (Dis­tances are never neg­a­tive, so we drop the minus sign.)

Reflec­tions in the axes

Fold­ing the plane along an axis sends each point to its mir­ror image.

  • Reflec­tion in the x-axis: (x,y)→(x,−y)(x, y) \to (x, -y).
  • Reflec­tion in the y-axis: (x,y)→(−x,y)(x, y) \to (-x, y).
  • Reflec­tion in the ori­gin (through OO to the other side): (x,y)→(−x,−y)(x, y) \to (-x, -y).

So the reflec­tion of (2,−5)(2, -5) in the x-axis is (2,5)(2, 5), in the y-axis is (−2,−5)(-2, -5), and in the ori­gin is (−2,5)(-2, 5).

Shapes on the plane

When the sides of a fig­ure run along grid lines, lengths can be read straight off the coor­di­nates.

Exam­ple 3

A rec­tan­gle has ver­tices A(1,1)A(1, 1), B(5,1)B(5, 1), C(5,4)C(5, 4) and D(1,4)D(1, 4). Find its length, breadth and area.

AA and BB have the same y-coor­di­nate, so ABAB is hor­i­zon­tal and its length is the dif­fer­ence of the x-coor­di­nates: 5−1=45 - 1 = 4 units. BB and CC have the same x-coor­di­nate, so BCBC is ver­ti­cal with length 4−1=34 - 1 = 3 units. The area is 4×3=124 \times 3 = 12 square units.

Exam­ple 4

Find the area of the tri­an­gle with ver­tices O(0,0)O(0, 0), A(6,0)A(6, 0) and B(0,4)B(0, 4).

OAOA lies along the x-axis with length 66 and OBOB along the y-axis with length 44. The axes are per­pen­dic­u­lar, so the tri­an­gle is right-angled at OO and its area is 12×6×4=12\displaystyle \frac{1}{2} \times 6 \times 4 = 12 square units.

Prac­tice

  1. Name the quad­rant or axis on which each point lies: (a) (−4,3)(-4, 3) (b) (5,−2)(5, -2) (c) (−3,−3)(-3, -3) (d) (0,−7)(0, -7) (e) (8,0)(8, 0)
  2. Write the abscissa and ordi­nate of (−9,4)(-9, 4).
  3. Write the coor­di­nates of the point on the x-axis that is 55 units to the left of the ori­gin.
  4. Write the coor­di­nates of the point on the y-axis that is 33 units below the ori­gin.
  5. How far is the point (7,−24)(7, -24) from the x-axis, and from the y-axis?
  6. Write the reflec­tions of (−3,7)(-3, 7) in the x-axis, in the y-axis and in the ori­gin.
  7. The point (a,b)(a, b) lies in quad­rant II. In which quad­rant does (b,a)(b, a) lie?
  8. A square has three ver­tices (0,0)(0, 0), (5,0)(5, 0) and (5,5)(5, 5). Find the fourth ver­tex and the area of the square.
  9. Find the area of the tri­an­gle with ver­tices (0,0)(0, 0), (8,0)(8, 0) and (0,−3)(0, -3).

Answers

Show answers
  1. (a) quad­rant II (b) quad­rant IV (c) quad­rant III (d) the y-axis (e) the x-axis
  2. Abscissa −9-9, ordi­nate 44
  3. (−5,0)(-5, 0)
  4. (0,−3)(0, -3)
  5. 2424 units from the x-axis, 77 units from the y-axis
  6. (−3,−7)(-3, -7), (3,7)(3, 7) and (3,−7)(3, -7)
  7. In quad­rant II, a<0a < 0 and b>0b > 0, so (b,a)(b, a) has a pos­i­tive x-coor­di­nate and a neg­a­tive y-coor­di­nate: quad­rant IV.
  8. (0,5)(0, 5); area 5×5=255 \times 5 = 25 square units
  9. Legs 88 and 33 along the axes: 12×8×3=12\displaystyle \frac{1}{2} \times 8 \times 3 = 12 square units