Expresswala Academy Mathematics Tuition

Introduction to Number Systems

MCQ test, Set 1

  • Set 1 of 10
  • 25 questions
  • 25 marks
  • 30 minutes

Download the PDF (with key sheet and solutions, 76.1 KB)

Choose one answer for each question, then check your score at the end. Each correct answer carries 1 mark; there is no negative marking.

  1. How many whole numbers are less than 99?
    Answer and solution

    Answer: (C) 99

    Whole numbers are the natural numbers along with 00: 0,1,2,3,…0, 1, 2, 3, \ldots

    Less than 99: 0,1,2,…,80, 1, 2, \ldots, 8. Counting 00 also, there are 99.

  2. Which of the following is an odd number?
    Answer and solution

    Answer: (C) 46514651

    4651=2×2325+14651 = 2 \times 2325 + 1

    Remainder is 11, so 46514651 is an odd number.

  3. Which of the following is a multiple of 77?
    Answer and solution

    Answer: (D) 9191

    7×13=917 \times 13 = 91, so 9191 is a multiple of 77.

    7575, 5757 and 107107 leave a remainder when divided by 77.

  4. The factors of 4646 are
    Answer and solution

    Answer: (D) 1,2,23,461, 2, 23, 46

    46=1×4646 = 1 \times 46

    =2×23= 2 \times 23

    Factors of 4646: 1,2,23,461, 2, 23, 46

  5. How many divisors does 6464 have?
    Answer and solution

    Answer: (B) 77

    64=1×6464 = 1 \times 64

    =2×32= 2 \times 32

    =4×16= 4 \times 16

    =8×8= 8 \times 8

    8×88 \times 8 gives the divisor 88 only once.

    Divisors: 1,2,4,8,16,32,641, 2, 4, 8, 16, 32, 64, so there are 77.

  6. Which of the following is a constant?
    Answer and solution

    Answer: (C) 1515

    A symbol which has a fixed value is called a constant.

    1515 has a fixed value.

  7. −1×q=-1 \times q =
    Answer and solution

    Answer: (C) −q-q

    As −1×a=−a-1 \times a = -a, −1×q=−q-1 \times q = -q.

  8. 7x+6x=7x + 6x =
    Answer and solution

    Answer: (A) 13x13x

    7x+6x=(7+6)x=13x7x + 6x = (7 + 6)x = 13x

  9. 11n−4n=11n - 4n =
    Answer and solution

    Answer: (B) 7n7n

    11n−4n=(11−4)n=7n11n - 4n = (11 - 4)n = 7n

  10. x×x×x×x=x \times x \times x \times x =
    Answer and solution

    Answer: (A) x4x^{4}

    xx is multiplied 44 times, so it is x4x^{4}.

  11. 382=38^{2} =
    Answer and solution

    Answer: (C) 14441444

    382=38×3838^{2} = 38 \times 38

    38×8=30438 \times 8 = 304

    38×3=11438 \times 3 = 114, written one place to the left: 11401140

    304+1140=1444304 + 1140 = 1444

  12. The square of 6767 is
    Answer and solution

    Answer: (A) 44894489

    672=67×6767^{2} = 67 \times 67

    67×7=46967 \times 7 = 469

    67×6=40267 \times 6 = 402, written one place to the left: 40204020

    469+4020=4489469 + 4020 = 4489

  13. 173=17^{3} =
    Answer and solution

    Answer: (C) 49134913

    173=17×17×1717^{3} = 17 \times 17 \times 17

    17×17=28917 \times 17 = 289, 289×17=4913289 \times 17 = 4913

    =4913= 4913

  14. Write 7×7×7×7×7×77 \times 7 \times 7 \times 7 \times 7 \times 7 in exponential form.
    Answer and solution

    Answer: (B) 767^{6}

    77 is multiplied by itself 66 times, so it is 767^{6}.

  15. The exponential form of 128128 with base 22 is
    Answer and solution

    Answer: (D) 272^{7}

    Divide by 22 again and again:

    128÷2=64128 \div 2 = 64, 64÷2=3264 \div 2 = 32, 32÷2=1632 \div 2 = 16

    16÷2=816 \div 2 = 8, 8÷2=48 \div 2 = 4, 4÷2=24 \div 2 = 2

    128=2×2×2×2×2×2×2=27128 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 = 2^{7}

  16. Which of the following numbers between 20002000 and 30003000 is divisible by 22?
    Answer and solution

    Answer: (A) 23322332

    A number is divisible by 22 if the digit at its unit place is 0,2,4,60, 2, 4, 6 or 88.

    The digit at the unit place of 23322332 is 22, so 23322332 is divisible by 22.

    The other three are not divisible.

  17. Which of the following numbers between 10001000 and 20002000 is divisible by 33?
    Answer and solution

    Answer: (B) 11911191

    A number is divisible by 33 if the sum of all its digits is divisible by 33.

    Sum of the digits of 11911191: 1+1+9+1=121 + 1 + 9 + 1 = 12

    1212 is divisible by 33 (12=3×412 = 3 \times 4), so 11911191 is divisible by 33.

    Each of the others fails the test.

  18. The smallest number greater than 720720 that is divisible by 33 is
    Answer and solution

    Answer: (D) 723723

    A number is divisible by 33 if the sum of all its digits is divisible by 33.

    721721: digit sum 1010, not divisible by 33

    722722: digit sum 1111, not divisible by 33

    723723: digit sum 1212, divisible by 33

  19. Which of the following numbers between 2000020000 and 3000030000 is divisible by 44?
    Answer and solution

    Answer: (B) 2985629856

    A number is divisible by 44 if its last two digits together are divisible by 44.

    Last two digits of 2985629856 together: 5656; 56=4×1456 = 4 \times 14, so 2985629856 is divisible by 44.

    Each of the others fails the test.

  20. Which of the following numbers between 30003000 and 40004000 is divisible by 55?
    Answer and solution

    Answer: (A) 37703770

    A number is divisible by 55 if the digit at its unit place is 00 or 55.

    The digit at the unit place of 37703770 is 00, so 37703770 is divisible by 55.

    The other three are not divisible.

  21. A number is divisible by 66 if it is divisible by
    Answer and solution

    Answer: (C) both 22 and 33

    A number is divisible by 66 if it is divisible by both 22 and 33.

  22. Which of the following numbers between 20002000 and 30003000 is divisible by 66?
    Answer and solution

    Answer: (A) 29042904

    A number is divisible by 66 if it is divisible by both 22 and 33.

    The digit at the unit place of 29042904 is 44, so 29042904 is divisible by 22.

    Sum of the digits of 29042904: 2+9+0+4=152 + 9 + 0 + 4 = 15

    1515 is divisible by 33 (15=3×515 = 3 \times 5), so 29042904 is divisible by 33.

    ∴\therefore 29042904 is divisible by 66.

    Each of the others fails the test.

  23. Which of the following numbers between 100100 and 200200 is divisible by 77?
    Answer and solution

    Answer: (D) 161161

    A number is divisible by 77 if the remaining part minus twice the unit digit is a multiple of 77 (or 00).

    161161: 16−1(2)=16−2=1416 - 1(2) = 16 - 2 = 14; 14=7×214 = 7 \times 2, a multiple of 77, so 161161 is divisible by 77.

    Each of the others fails the test.

  24. To test 309309 for divisibility by 77, twice the unit digit is subtracted from the remaining part. The result is
    Answer and solution

    Answer: (B) 1212

    Remaining part =30= 30, unit digit =9= 9

    30−9(2)=30−18=1230 - 9(2) = 30 - 18 = 12

  25. Among 2,3,4,52, 3, 4, 5 and 66, the number 1753817538 is divisible by
    Answer and solution

    Answer: (D) 2,32, 3 and 66 only

    The digit at the unit place of 1753817538 is 88, so 1753817538 is divisible by 22.

    Sum of the digits of 1753817538: 1+7+5+3+8=241 + 7 + 5 + 3 + 8 = 24

    2424 is divisible by 33 (24=3×824 = 3 \times 8), so 1753817538 is divisible by 33.

    Last two digits of 1753817538 together: 3838; 38=4×9+238 = 4 \times 9 + 2, so 1753817538 is not divisible by 44.

    The digit at the unit place of 1753817538 is 88, so 1753817538 is not divisible by 55.

    Divisible by both 22 and 33 means divisible by 66.

    So 1753817538 is divisible by 2,32, 3 and 66.